提取文件路径并复制到 pwd
Extract filepaths and copy to pwd
如何提取 *.so 个文件的路径并将它们复制到 pwd？我认为它们可以通过正则表达式提取（在 => 和 ( 之间），但不知道如何。
linux-vdso.so.1 (0x00007ffdd63c7000)
libcurl.so.4 (0x00007f5462ffd000)
libjansson.so.4 (0x00007f5462fee000)
libpthread.so.0 => /lib/x86_64-linux-gnu/libpthread.so.0 (0x00007f5462fad000)
libcrypto.so.1.1 => /usr/lib/x86_64-linux-gnu/libcrypto.so.1.1 (0x00007f5462cd7000)
libgmp.so.10 => /usr/lib/x86_64-linux-gnu/libgmp.so.10 (0x00007f5462c53000)
libstdc++.so.6 => /usr/lib/x86_64-linux-gnu/libstdc++.so.6 (0x00007f5462a70000)
libm.so.6 (0x00007f5462921000)
libc.so.6 => /lib/x86_64-linux-gnu/libc.so.6 (0x00007f546272f000)
libnghttp2.so.14 => /usr/lib/x86_64-linux-gnu/libnghttp2.so.14 (0x00007f5462706000)
libidn2.so.0 => /usr/lib/x86_64-linux-gnu/libidn2.so.0 (0x00007f54626e5000)
librtmp.so.1 => /usr/lib/x86_64-linux-gnu/librtmp.so.1 (0x00007f54626c5000)
libssh.so.4 (0x00007f5462655000)
libpsl.so.5 => /usr/lib/x86_64-linux-gnu/libpsl.so.5 (0x00007f5462642000)
libssl.so.1.1 => /usr/lib/x86_64-linux-gnu/libssl.so.1.1 (0x00007f54625af000)
libgssapi_krb5.so.2 => /usr/lib/x86_64-linux-gnu/libgssapi_krb5.so.2 (0x00007f5462562000)
libldap_r-2.4.so.2 => /usr/lib/x86_64-linux-gnu/libldap_r-2.4.so.2 (0x00007f546250c000)
liblber-2.4.so.2 => /usr/lib/x86_64-linux-gnu/liblber-2.4.so.2 (0x00007f54624fb000)
libbrotlidec.so.1 => /usr/lib/x86_64-linux-gnu/libbrotlidec.so.1 (0x00007f54624eb000)
libz.so.1 => /lib/x86_64-linux-gnu/libz.so.1 (0x00007f54624cf000)
/lib64/ld-linux-x86-64.so.2 (0x00007f54632a1000)
libdl.so.2 => /lib/x86_64-linux-gnu/libdl.so.2 (0x00007f54624c9000)
libgcc_s.so.1 => /lib/x86_64-linux-gnu/libgcc_s.so.1 (0x00007f54624ae000)
libunistring.so.2 => /usr/lib/x86_64-linux-gnu/libunistring.so.2 (0x00007f546232c000)
libgnutls.so.30 => /usr/lib/x86_64-linux-gnu/libgnutls.so.30 (0x00007f5462154000)
libhogweed.so.5 => /usr/lib/x86_64-linux-gnu/libhogweed.so.5 (0x00007f546211c000)
libnettle.so.7 => /usr/lib/x86_64-linux-gnu/libnettle.so.7 (0x00007f54620e2000)
libkrb5.so.3 => /usr/lib/x86_64-linux-gnu/libkrb5.so.3 (0x00007f5462005000)
libk5crypto.so.3 => /usr/lib/x86_64-linux-gnu/libk5crypto.so.3 (0x00007f5461fd4000)
libcom_err.so.2 => /lib/x86_64-linux-gnu/libcom_err.so.2 (0x00007f5461fcd000)
libkrb5support.so.0 => /usr/lib/x86_64-linux-gnu/libkrb5support.so.0 (0x00007f5461fbc000)
libresolv.so.2 => /lib/x86_64-linux-gnu/libresolv.so.2 (0x00007f5461fa0000)
libsasl2.so.2 => /usr/lib/x86_64-linux-gnu/libsasl2.so.2 (0x00007f5461f83000)
libgssapi.so.3 => /usr/lib/x86_64-linux-gnu/libgssapi.so.3 (0x00007f5461f3e000)
libbrotlicommon.so.1 => /usr/lib/x86_64-linux-gnu/libbrotlicommon.so.1 (0x00007f5461f1b000)
libp11-kit.so.0 => /usr/lib/x86_64-linux-gnu/libp11-kit.so.0 (0x00007f5461de3000)
libtasn1.so.6 => /usr/lib/x86_64-linux-gnu/libtasn1.so.6 (0x00007f5461dcd000)
libkeyutils.so.1 => /lib/x86_64-linux-gnu/libkeyutils.so.1 (0x00007f5461dc6000)
libheimntlm.so.0 => /usr/lib/x86_64-linux-gnu/libheimntlm.so.0 (0x00007f5461dba000)
libkrb5.so.26 => /usr/lib/x86_64-linux-gnu/libkrb5.so.26 (0x00007f5461d27000)
libasn1.so.8 => /usr/lib/x86_64-linux-gnu/libasn1.so.8 (0x00007f5461c7e000)
libhcrypto.so.4 => /usr/lib/x86_64-linux-gnu/libhcrypto.so.4 (0x00007f5461c46000)
libroken.so.18 => /usr/lib/x86_64-linux-gnu/libroken.so.18 (0x00007f5461c2d000)
libffi.so.7 => /usr/lib/x86_64-linux-gnu/libffi.so.7 (0x00007f5461c21000)
libwind.so.0 => /usr/lib/x86_64-linux-gnu/libwind.so.0 (0x00007f5461bf7000)
libheimbase.so.1 => /usr/lib/x86_64-linux-gnu/libheimbase.so.1 (0x00007f5461be3000)
libhx509.so.5 => /usr/lib/x86_64-linux-gnu/libhx509.so.5 (0x00007f5461b95000)
libsqlite3.so.0 => /usr/lib/x86_64-linux-gnu/libsqlite3.so.0 (0x00007f5461a6c000)
libcrypt.so.1 => /lib/x86_64-linux-gnu/libcrypt.so.1 (0x00007f5461a31000)
为了解释我是如何遇到这个问题的：我在本地 linux 编译了一个二进制文件并尝试在远程 运行 它（无法在远程服务器上编译）。但是，由于缺乏依赖性，它不能是 运行。所以我正在将 *.so 文件复制到服务器。
您可以使用 awk '/=>/{print }'.
这假设您要提取的路径中没有空格，并故意跳过没有字符串 =>.
的行
然后您可以通过几种不同的方式将文件复制到您的工作目录。这是使用 while 循环的方法：
<your command> | awk '/=>/{print }' | while read -r file; do
cp "$file" .
done
如何提取 *.so 个文件的路径并将它们复制到 pwd？我认为它们可以通过正则表达式提取（在 => 和 ( 之间），但不知道如何。
linux-vdso.so.1 (0x00007ffdd63c7000)
libcurl.so.4 (0x00007f5462ffd000)
libjansson.so.4 (0x00007f5462fee000)
libpthread.so.0 => /lib/x86_64-linux-gnu/libpthread.so.0 (0x00007f5462fad000)
libcrypto.so.1.1 => /usr/lib/x86_64-linux-gnu/libcrypto.so.1.1 (0x00007f5462cd7000)
libgmp.so.10 => /usr/lib/x86_64-linux-gnu/libgmp.so.10 (0x00007f5462c53000)
libstdc++.so.6 => /usr/lib/x86_64-linux-gnu/libstdc++.so.6 (0x00007f5462a70000)
libm.so.6 (0x00007f5462921000)
libc.so.6 => /lib/x86_64-linux-gnu/libc.so.6 (0x00007f546272f000)
libnghttp2.so.14 => /usr/lib/x86_64-linux-gnu/libnghttp2.so.14 (0x00007f5462706000)
libidn2.so.0 => /usr/lib/x86_64-linux-gnu/libidn2.so.0 (0x00007f54626e5000)
librtmp.so.1 => /usr/lib/x86_64-linux-gnu/librtmp.so.1 (0x00007f54626c5000)
libssh.so.4 (0x00007f5462655000)
libpsl.so.5 => /usr/lib/x86_64-linux-gnu/libpsl.so.5 (0x00007f5462642000)
libssl.so.1.1 => /usr/lib/x86_64-linux-gnu/libssl.so.1.1 (0x00007f54625af000)
libgssapi_krb5.so.2 => /usr/lib/x86_64-linux-gnu/libgssapi_krb5.so.2 (0x00007f5462562000)
libldap_r-2.4.so.2 => /usr/lib/x86_64-linux-gnu/libldap_r-2.4.so.2 (0x00007f546250c000)
liblber-2.4.so.2 => /usr/lib/x86_64-linux-gnu/liblber-2.4.so.2 (0x00007f54624fb000)
libbrotlidec.so.1 => /usr/lib/x86_64-linux-gnu/libbrotlidec.so.1 (0x00007f54624eb000)
libz.so.1 => /lib/x86_64-linux-gnu/libz.so.1 (0x00007f54624cf000)
/lib64/ld-linux-x86-64.so.2 (0x00007f54632a1000)
libdl.so.2 => /lib/x86_64-linux-gnu/libdl.so.2 (0x00007f54624c9000)
libgcc_s.so.1 => /lib/x86_64-linux-gnu/libgcc_s.so.1 (0x00007f54624ae000)
libunistring.so.2 => /usr/lib/x86_64-linux-gnu/libunistring.so.2 (0x00007f546232c000)
libgnutls.so.30 => /usr/lib/x86_64-linux-gnu/libgnutls.so.30 (0x00007f5462154000)
libhogweed.so.5 => /usr/lib/x86_64-linux-gnu/libhogweed.so.5 (0x00007f546211c000)
libnettle.so.7 => /usr/lib/x86_64-linux-gnu/libnettle.so.7 (0x00007f54620e2000)
libkrb5.so.3 => /usr/lib/x86_64-linux-gnu/libkrb5.so.3 (0x00007f5462005000)
libk5crypto.so.3 => /usr/lib/x86_64-linux-gnu/libk5crypto.so.3 (0x00007f5461fd4000)
libcom_err.so.2 => /lib/x86_64-linux-gnu/libcom_err.so.2 (0x00007f5461fcd000)
libkrb5support.so.0 => /usr/lib/x86_64-linux-gnu/libkrb5support.so.0 (0x00007f5461fbc000)
libresolv.so.2 => /lib/x86_64-linux-gnu/libresolv.so.2 (0x00007f5461fa0000)
libsasl2.so.2 => /usr/lib/x86_64-linux-gnu/libsasl2.so.2 (0x00007f5461f83000)
libgssapi.so.3 => /usr/lib/x86_64-linux-gnu/libgssapi.so.3 (0x00007f5461f3e000)
libbrotlicommon.so.1 => /usr/lib/x86_64-linux-gnu/libbrotlicommon.so.1 (0x00007f5461f1b000)
libp11-kit.so.0 => /usr/lib/x86_64-linux-gnu/libp11-kit.so.0 (0x00007f5461de3000)
libtasn1.so.6 => /usr/lib/x86_64-linux-gnu/libtasn1.so.6 (0x00007f5461dcd000)
libkeyutils.so.1 => /lib/x86_64-linux-gnu/libkeyutils.so.1 (0x00007f5461dc6000)
libheimntlm.so.0 => /usr/lib/x86_64-linux-gnu/libheimntlm.so.0 (0x00007f5461dba000)
libkrb5.so.26 => /usr/lib/x86_64-linux-gnu/libkrb5.so.26 (0x00007f5461d27000)
libasn1.so.8 => /usr/lib/x86_64-linux-gnu/libasn1.so.8 (0x00007f5461c7e000)
libhcrypto.so.4 => /usr/lib/x86_64-linux-gnu/libhcrypto.so.4 (0x00007f5461c46000)
libroken.so.18 => /usr/lib/x86_64-linux-gnu/libroken.so.18 (0x00007f5461c2d000)
libffi.so.7 => /usr/lib/x86_64-linux-gnu/libffi.so.7 (0x00007f5461c21000)
libwind.so.0 => /usr/lib/x86_64-linux-gnu/libwind.so.0 (0x00007f5461bf7000)
libheimbase.so.1 => /usr/lib/x86_64-linux-gnu/libheimbase.so.1 (0x00007f5461be3000)
libhx509.so.5 => /usr/lib/x86_64-linux-gnu/libhx509.so.5 (0x00007f5461b95000)
libsqlite3.so.0 => /usr/lib/x86_64-linux-gnu/libsqlite3.so.0 (0x00007f5461a6c000)
libcrypt.so.1 => /lib/x86_64-linux-gnu/libcrypt.so.1 (0x00007f5461a31000)
为了解释我是如何遇到这个问题的：我在本地 linux 编译了一个二进制文件并尝试在远程 运行 它（无法在远程服务器上编译）。但是，由于缺乏依赖性，它不能是 运行。所以我正在将 *.so 文件复制到服务器。
您可以使用 awk '/=>/{print }'.
这假设您要提取的路径中没有空格，并故意跳过没有字符串 =>.
然后您可以通过几种不同的方式将文件复制到您的工作目录。这是使用 while 循环的方法：
<your command> | awk '/=>/{print }' | while read -r file; do
cp "$file" .
done