Python

Question

我有这样的字符串：

text = "The best language in the word is $python at now"

以及要搜索的单词列表：

keywords = ["PYTHON","PHP","JAVA","COBOL","CPP","VB","HTML"]

如何得到“PYTHON”作为结果？

Answer 1

这段代码对我有用，但你必须去掉 python 之前的 $:

text = "The best language in the word is python at now"

keywords = ["PYTHON","PHP","JAVA","COBOL","CPP","VB","HTML"]

upper_text = text.upper()

ar_text = upper_text.split()

for word in keywords:
    if word in ar_text:
        print(word)

Answer 2

在 python 中，您可以使用 in 运算符轻松检查字符串是否包含另一个字符串。

只需检查每个关键字的字符串，并记住大小写相同。

你可以使用一根线

[print(x) for x in keywords if x in text.upper()]

或多个

for x in keywords:
    if x in text.upper():
        print(x)

在您的情况下，以下示例将输出 PYTHON:

text     = "The best language in the word is $python at now"
keywords = ["PYTHON","PHP","JAVA","COBOL","CPP","VB","HTML"] 

[print(x) for x in keywords if x in text.upper()] #PYTHON

祝你有愉快的一天。

编辑

正如 Malo 所指出的，我可能更好的风格是将输出传递给一个变量，然后再打印出来。

text     = "The best language in the word is $python at now"
keywords = ["PYTHON","PHP","JAVA","COBOL","CPP","VB","HTML"] 

matches  = [x for x in keywords if x in text.upper()]

for x in matches: print(x) # PYTHON

Answer 3

这将使用 find 来检查字符串中是否有任何列表项（不区分大小写，因为这是你要问的）：

results = []
for keyword in keywords:
    if text.lower().find(keyword.lower()) != -1:
        results.append(keyword)

print(results)

Python - 在字符串的单词列表中搜索单词的匹配项

Python - Search for a match for a word in a list of words in a string

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