Python VLC - 下一首曲目

Question

我正在 Python 到运行在 Raspberry Pi 上编写一个程序来控制我的 Wurlitzer 自动点唱机。当前程序接受“记录选择”代码（A1、B1、C4 等），将这些代码添加到播放列表，然后执行该列表。我的问题是，一旦歌曲开始播放，我希望能够按下一个按钮（当前代码中的“Y”）来跳过当前播放的歌曲。我无法让它工作。

如果我使用“player.next()”，我会得到一个错误：'MediaPlayer' object has no attribute 'next'.

我试图停止播放器并重新启动它（认为它会播放播放列表中的下一首歌曲。这甚至没有停止播放器。

如果可以避免，我不想使用子流程。我想在 Python 内想出一种方法来跳过。如何做到这一点？

import os, sys, csv, vlc, time, threading
from pynput.keyboard import Key, Listener

DefaultUSBPath="/media/pi"
PlayHistory="PlayHistory.csv"

#
# Declare variables
#
USBDrive = None
Action = None
Playlist = []
SelectionCount = []
Sel_char = None
#
# Find the USB Drive
#
for item in os.listdir(DefaultUSBPath):
    if os.path.isdir(os.path.join(DefaultUSBPath, item)):
        if USBDrive is None:
            USBDrive =  os.path.join(DefaultUSBPath, item)
        else:
            USBDrive = USBDrive + ";" + os.path.join(DefaultUSBPath, item)
if USBDrive is None:
    print ("Error(0) - No USB Drive detected")
    sys.exit()
elif ";" in USBDrive:
    print ("Error(1) - More than one USB Drive detected.")
    sys.exit()
#
# Adding to playlist - Returns directory contents and adds to playlist
#
def addplaylist(track):
    list = None
    if os.path.isdir(os.path.join(USBDrive, track)):
        files = [f for f in os.listdir(os.path.join(USBDrive, track)) if os.path.isfile(os.path.join(USBDrive, track, f))]
        for f in files:
            if list is None:
                list = os.path.join(USBDrive, track, f)
            else:
                list = list + ";" + os.path.join(USBDrive, track, f)
    else:
        print ("Error(2) - Selection is invalid")
    if list is not None:
        if ";" in list:
            list = list.split(";")
    else:
        print ("Error(3) - Selection has no media")
    return list
#
# MediaPlayer function
#
def MusicPlayer(P):
    global Playlist, player
    while len(Playlist) > 0:
        song=Playlist.pop(0)
        print("Song: ")
        print(song)
        player=vlc.MediaPlayer(song)
        player.play()
#
# Define keyboard actions
#
def on_press(key):
    global Action, Playlist, player
    try:
        Sel_char = int(key.char)
    except:
        try:
            Sel_char = str(key.char)
            Sel_char = Sel_char.upper()
        except:
            Sel_char = None
    if Sel_char == "Z":
        return False
    elif Sel_char == "Y":
        print("Skip")
        #player.next()     This line causes 'MediaPlayer' object has no attribute 'next'
        time.sleep(1)
        MusicPlayer(Playlist)
    elif type(Sel_char) == str:
        Action = Sel_char
    elif type(Sel_char) == int:
        Action = Action + str(Sel_char)
        print("Action: " + Action)
        Plist = addplaylist(Action)
        if Plist is not None:
            print("Added to playlist")
            Playlist.append(Plist)
            print(Plist)
            MusicPlayer(Playlist)
    else:
        pass
#
# Read keyboard input
#
with Listener(on_press=on_press) as listener:
    listener.join()
print ("")
print ("Have a nice day!")
print ("")
sys.exit()

Answer 1

根据您的编码方式，我希望您必须停止它，从列表中删除当前媒体，然后重新启动它。

但是运行一个 media_list_player 可能会更好，请参阅下面的基本版本。请注意，我在 Linux 上，不得不破解一些代码来获取键输入，而不是使用特定的库或花时间在上面，但它应该足以让你使用。

Edit

抱歉，使用 media_list_player 时有一个更简单的方法，但如果您想要更好的控制，您应该使用 media_list_player 来控制列表的索引，或者要完全控制，请使用 a media_player_new() 但这超出了这个问题的范围。（我会把原来的答案留在这段代码下面，因为它可能会有用）

import vlc
import time

## pinched from vlc for keyboard input
import termios
import tty
import sys

mymedia = ["vp.mp3","vp1.mp3","happy.mp3","V1.mp4"]

def getch():  # getchar(), getc(stdin)  #PYCHOK flake
    fd = sys.stdin.fileno()
    old = termios.tcgetattr(fd)
    try:
        tty.setraw(fd)
        ch = sys.stdin.read(1)
    finally:
        termios.tcsetattr(fd, termios.TCSADRAIN, old)
    return ch
## end pinched code

def jukebox():
    player.play_item_at_index(0)    
    while True:
        time.sleep(0.25)
        k = getch()
        if k == "n": #Next
            player.next()
        if k == "p": #Previous
            player.previous()
        if k == " ": #Pause
            player.pause()
        if k == "q": #Quit
            player.stop()
            return True

    player.next()
            
vlc_instance = vlc.Instance('--no-xlib --quiet ') # no-xlib for linux and quiet don't complain
player = vlc_instance.media_list_player_new()
Media = vlc_instance.media_list_new(mymedia)
player.set_media_list(Media)

print("Welcome to Jukebox")
print("Options - space = Play/Pause, n = Next, p = Previous, q = Quit")
print("Media",mymedia)

jukebox()

Original code

import vlc
import time

## pinched from vlc for keyboard input
import termios
import tty
import sys

def getch():  # getchar(), getc(stdin)  #PYCHOK flake
    fd = sys.stdin.fileno()
    old = termios.tcgetattr(fd)
    try:
        tty.setraw(fd)
        ch = sys.stdin.read(1)
    finally:
        termios.tcsetattr(fd, termios.TCSADRAIN, old)
    return ch
## end pinched code


vlc_instance = vlc.Instance()
player = vlc_instance.media_list_player_new()
mymedia = ["vp.mp3","vp1.mp3","happy.mp3"]
Media = vlc_instance.media_list_new(mymedia)
player.set_media_list(Media)
for index, name in enumerate(mymedia):
    print("Playing:",name)
    player.play_item_at_index(index)    
    time.sleep(1)
    while player.get_state() != 6:
        time.sleep(1)
        k = getch()
        if k == "y":
            player.stop()
            break

Python VLC - 下一首曲目

Python VLC - Next track

python

vlc

raspberry-pi4