地图函数不传递列表中的最后一项

Question

我创建了一个功能，可以在 Gmail 中搜索我的收件箱，然后将每封邮件分为 3 个类别（姓名、电子邮件和 body）。然后它将它粘贴到 Google Sheet 的 3 列中。但是，当我运行时，它只会将姓名和电子邮件粘贴到前两列。问题在于 body。即使，当我运行 Logger.log(d.getPlainBody()); 它显示了我正在寻找的 body 文本。

我使用的代码：

// extract emails from label in Gmail
function extractEmails() {
  
  // get the spreadsheet
  var ss = SpreadsheetApp.getActiveSpreadsheet();
  var sheet = ss.getActiveSheet();
  
  // get all email threads that match label from Sheet
  var threads = GmailApp.getInboxThreads();
  
  // get all the messages for the current batch of threads
  var messages = GmailApp.getMessagesForThreads(threads);
  
  var emailArray = [];
  
  // get array of email addresses
  messages.forEach(
    function(message) {
    message.forEach(
      function(d) {
      emailArray.push(d.getFrom(),d.getTo(),d.getPlainBody());
      Logger.log(d.getPlainBody());
    });
  });
  
  // de-duplicate the array
  var uniqueEmailArray = emailArray.filter(function(item, pos) {
    return emailArray.indexOf(item) == pos;
  });
  
  var cleanedEmailArray = uniqueEmailArray.map(
    function(el) {
      
      var matches = el.match(/\s*"?([^"]*)"?\s+<(.+)>/);
      
      if (matches) {
        name = matches[1]; 
        email = matches[2];
        body = matches[3];
      }
      
      return [name, email, body];
      
  });
  
  // clear any old data
  sheet.getRange(2,1,sheet.getLastRow(), 3).clearContent();
  
  // paste in new names and emails
  var printing = sheet.getRange(2 ,1,cleanedEmailArray.length, 3);
  printing.setValues(cleanedEmailArray);


}

Answer 1

您的逻辑似乎有问题，尤其是在地图功能上。您实际上是在匹配每个元素，而不是每条消息。而且您的正则表达式仅捕获 2 种模式，因此预计 matches[3] 到 return 空白。

我稍微修改了你的代码。他们是：

将变量作为数组（消息）的元素传递，并删除 getTo 因为您没有使用它。但如果你是，请随时再次添加。

  // get array of email addresses
  messages.forEach(function(message) {
    message.forEach(function(d) {
      // Push the data as array to easily process them
      // Removed getTo as you only are getting name and email from getFrom data based on your regex
      emailArray.push([d.getFrom(),d.getPlainBody()]);
    });
  });

Map 函数已替换为更简单的 forEach。这是可能的，因为我们将消息数据作为上面的数组。

  var cleanedEmailArray = [];
  uniqueEmailArray.forEach(function(message){
    // match name and email from pattern "name <email>" in d.getFrom()
    // only pass match[1] and match[2], since match[0] = message[0]
    [, name, email] = message[0].match(/\s*"?([^"]*)"?\s+<(.+)>/);
    // get body from d.getPlainBody()
    body = message[1];
    cleanedEmailArray.push([name, email, body])
  });

（吹毛求疵）你没有使用 printing 所以我合并了 2 行

  // paste in new names and emails
  sheet.getRange(2 ,1,cleanedEmailArray.length, 3).setValues(cleanedEmailArray);

这就是您的代码的样子：

代码：

function extractEmails() {
  var ss = SpreadsheetApp.getActiveSpreadsheet();
  var sheet = ss.getActiveSheet();
  var threads = GmailApp.getInboxThreads();
  var messages = GmailApp.getMessagesForThreads(threads);
  var emailArray = [], cleanedEmailArray = [];

  messages.forEach(function(message) {
    message.forEach(function(d) {
      emailArray.push([d.getFrom(),d.getPlainBody()]);
    });
  });

  var uniqueEmailArray = emailArray.filter(function(item, pos) {
    return emailArray.indexOf(item) == pos;
  });
  
  uniqueEmailArray.forEach(function(message){
    [, name, email] = message[0].match(/\s*"?([^"]*)"?\s+<(.+)>/);
    body = message[1];
    cleanedEmailArray.push([name, email, body])
  });

  sheet.getRange(2,1,sheet.getLastRow(), 3).clearContent();
  sheet.getRange(2 ,1,cleanedEmailArray.length, 3).setValues(cleanedEmailArray);
}

输出：

Answer 2

如果有人来这里，我已经修改了 NaziA 的一些代码并创建了一个 InboxScraper(The article has step by step with many images). I leave the code below. From the google app script connected to your Google Sheets it will access your Gmail and Scrape email (Column A) and body (Column B). I have posted images in an article。


function extractEmails() {
  var ss = SpreadsheetApp.getActiveSpreadsheet();
  var sheet = ss.getActiveSheet();
  var threads = GmailApp.getInboxThreads();
  var messages = GmailApp.getMessagesForThreads(threads);
  var emailArray = [], cleanedEmailArray = [];

  messages.forEach(function(message) {
    message.forEach(function(d) {
      emailArray.push([d.getFrom(),d.getPlainBody()]);
    });
  });

  var uniqueEmailArray = emailArray.filter(function(item, pos) {
    return emailArray.indexOf(item) == pos;
  });
  
  uniqueEmailArray.forEach(function(message){
    [, name, email] = message[0].match(/\s*"?([^"]*)"?\s+<(.+)>/);
    body = message[1];
    cleanedEmailArray.push([name, email, body])
  });

  sheet.getRange(2,1,sheet.getLastRow(), 3).clearContent();
  sheet.getRange(2 ,1,cleanedEmailArray.length, 3).setValues(cleanedEmailArray);
}

地图函数不传递列表中的最后一项

Map function does not pass the last item in the list

javascript

gmail

google-sheets

google-apps-script

代码：

输出：