根据构建风格从清单中删除权限

Question

我有 3 种口味，每种都应该有不同的权限。我的口味定义如下：

  allPermissions {
        dimension "permissions"
        manifestPlaceholders = [excludeCallLogPermission: "false", excludeSmsPermission: "false"]
    }

    noSmsPermission {
        dimension "permissions"
        manifestPlaceholders = [excludeSmsPermission: "true"]
    }

    noSmsNoCallogPermission {
        dimension "permissions"
        manifestPlaceholders = [excludeCallLogPermission: "true", excludeSmsPermission: "true"]
    }

在我的清单中我有这个：

 <uses-permission android:name="android.permission.READ_CALL_LOG"
    tools:remove="${excludeCallLogPermission}"/>
<uses-permission android:name="android.permission.SEND_SMS"
    tools:remove="${excludeSmsPermission}"/>enter code here

它不会给出任何错误和构建，但该应用程序具有上述 2 个权限，即使 flavor 将两者都设置为 false 因此它无法正常工作。

如果我尝试使用 tools:node="${excludeSmsPermission}" 并将其值设置为删除，我会收到此警告

Answer 1

找到了一个可行的 hackish 解决方案

allPermissions {
        dimension "permissions"
        manifestPlaceholders = [extraPermission1: "android.permission.SEND_SMS", extraPermission2: "android.permission.READ_CALL_LOG"]
    }

    noSmsPermission {
        dimension "permissions"
        manifestPlaceholders = [extraPermission1: "android.permission.placeholder", extraPermission2: "android.permission.READ_CALL_LOG"]
    }

    noSmsNoCallogPermission {
        dimension "permissions"
        manifestPlaceholders = [extraPermission1: "android.permission.placeholder", extraPermission2: "android.permission.placeholder"]
    }

和

 <uses-permission android:name="${extraPermission1}"/>
<uses-permission android:name="${extraPermission2}"/>

根据构建风格从清单中删除权限

Removing permissions from manifest depending on build flavor

android

permissions

manifest