复制到剪贴板 - Android studio (getString - settextView)

Question

我正在尝试向 settextview 添加“复制”按钮。

这是我的完整代码：

public class activity_tasks extends AppCompatActivity {
    private Button button_refresh;
    TextView textView;
    TextView textView4;
    private AdView mAdView;


    @RequiresApi(api = Build.VERSION_CODES.M)
    @Override
    protected void onCreate(Bundle savedInstanceState) {
        super.onCreate(savedInstanceState);
        setContentView(R.layout.activity_tasks);

        MobileAds.initialize(this, new OnInitializationCompleteListener() {
            @Override
            public void onInitializationComplete(InitializationStatus initializationStatus) {
            }
        });
        mAdView = findViewById(R.id.adView);
        AdRequest adRequest = new AdRequest.Builder().build();
        mAdView.loadAd(adRequest);

        button_refresh = findViewById(R.id.button_refresh);

        button_refresh.setOnClickListener(v -> {

            finish();
            startActivity(getIntent());
            overridePendingTransition(0, 0);
        });

        Button button = findViewById(R.id.button1);
        Button button_copy = findViewById(R.id.button_copy);
        button.setOnClickListener(v -> showInfo());
        textView = findViewById(R.id.textView4);
        downloadJSON();




    }

    private void downloadJSON() {


        @SuppressLint("StaticFieldLeak")
        class DownloadJSON extends AsyncTask<Void, Void, String> {

            @Override
            protected void onPreExecute() {
                super.onPreExecute();
            }


            @Override
            protected void onPostExecute(String s) {

                try {
                    settextView(s);
                } catch (JSONException e) {
                    e.printStackTrace();
                }
            }

            @Override
            protected String doInBackground(Void... voids) {
                try {
                    URL url = new URL("https://www.URL.app/api/tasks.php");
                    HttpURLConnection con = (HttpURLConnection) url.openConnection();
                    StringBuilder sb = new StringBuilder();
                    BufferedReader bufferedReader = new BufferedReader(new InputStreamReader(con.getInputStream()));
                    String json;
                    while ((json = bufferedReader.readLine()) != null) {
                        sb.append(json).append("\n");
                    }
                    return sb.toString().trim();
                } catch (Exception e) {
                    return null;
                }
            }
        }
        DownloadJSON getJSON = new DownloadJSON();
        getJSON.execute();
    }

    private void settextView(String json) throws JSONException {
        JSONArray jsonArray = new JSONArray(json);
        String[] tasks = new String[jsonArray.length()];
        for (int i = 0; i < jsonArray.length(); i++) {
            JSONObject obj = jsonArray.getJSONObject(i);
            tasks[i] = obj.getString("Task_title") + ".\n\n" + obj.getString("task_description");


            textView.setText(tasks[0]);


        }

我的问题是我不确定将以下代码放在哪里：

            button_copy.setOnClickListener(v -> {

                ClipboardManager clipboard = (ClipboardManager)getApplicationContext().getSystemService(getApplicationContext().CLIPBOARD_SERVICE);
                ClipData clip = ClipData.newPlainText("", obj.getString("Task_title") + ".\n\n" + obj.getString("task_description"));
                clipboard.setPrimaryClip(clip);
                Toast.makeText(getApplicationContext(), "Copied to clipboard!", Toast.LENGTH_LONG).show();

            });

我试过将它放在 settextView 中，但是当我登陆页面并生成文本时，它会自动复制 - 但我希望它归因于一个按钮，而不是自动复制。作为参考，我的 activity_list.xml 中的按钮是 button_copy.

Answer 1

为了更方便，将按钮放在 settextview 内。当进程还在进行时，我们需要用按钮hide/do一些东西。您可以在为按钮创建 .setVisibility 时隐藏它。之后，您可以显示按钮。

  private void settextView(String json) throws JSONException {
        JSONArray jsonArray = new JSONArray(json);
        String[] tasks = new String[jsonArray.length()];
        for (int i = 0; i < jsonArray.length(); i++) {
            JSONObject obj = jsonArray.getJSONObject(i);
            tasks[i] = obj.getString("Task_title") + ".\n\n" + obj.getString("task_description");

        textView.setText(tasks[0]);
        button_copy.setVisibility(View.VISIBLE); //Visible it
        setBtnCopyOnClick(tasks[0]); //Here


    }

然后为btn创建一个方法

private void setBtnCopyOnClick(String text){
 button_copy.setOnClickListener(v -> {

            ClipboardManager clipboard = (ClipboardManager)getApplicationContext().getSystemService(getApplicationContext().CLIPBOARD_SERVICE);
            ClipData clip = ClipData.newPlainText("", text);
            clipboard.setPrimaryClip(clip);
            Toast.makeText(getApplicationContext(), "Copied to clipboard!", Toast.LENGTH_LONG).show();

        });
}

Answer 2

感谢 Ticherhaz 让我到达那里！

按照他的指示，问题是字符串的属性不正确，所以新代码是：

    private void setBtnCopyOnClick(String task) {
        Button button_copy = findViewById(R.id.button_copy);
        button_copy.setOnClickListener(v -> {
            ClipboardManager clipboard = (ClipboardManager)getApplicationContext().getSystemService(getApplicationContext().CLIPBOARD_SERVICE);
            ClipData clip = ClipData.newPlainText("", task);
            clipboard.setPrimaryClip(clip);
            Toast.makeText(getApplicationContext(), "Copied to clipboard!", Toast.LENGTH_LONG).show();

        });

复制到剪贴板 - Android studio (getString - settextView)

Copy to clipboard - Android studio (getString - settextView)

java

android

android-studio

clipboard