Django 休息框架中的自定义 kwarg

Question

今天我有 2 个 URL

router.register(r'question_type', QuestionTypeViewSet)
router.register(r'question', QuestionViewSet)

但我需要这样的东西

router.register(r'question_type', QuestionTypeViewSet)
router.register(r'question_type/question_type_pk/question', QuestionViewSet)

我的观点

class QuestionTypeViewSet(viewsets.ModelViewSet):

   serializer_class = QuestionTypeSerializer
   queryset = QuestionType.objects.all()

我想用 QuestionViewSet 做什么

class QuestionViewSet(viewsets.ModelViewSet):

   serializer_class = QuestionSerializer

   def get_queryset(self):

       queryset = Question.objects.filter(
           question_type__id=self.kwargs['question_type_id'])

       return queryset

我应该如何做题url？

Answer 1

根据文档的这个 session，您可以通过向 QuestionViewSet 视图集添加额外的操作来实现此目的。

根据此处的文档，可以了解如何实现 r'question_type/{pk}/question'

from rest_framework.decorators import action

.........

class QuestionViewSet(viewsets.ModelViewSet):
    """ your current code """
    
    @action(detail=True, methods=['post'])
    def question(self, request, pk=True):
        serializer = YourQuestionSerializer(data=request.data)
        if serializer.is_valid(): 
            """ your logic here """

Django 休息框架中的自定义 kwarg

Custom kwarg in Django rest framework

django

django-rest-framework

django-urls