Terraform 'aws_secretsmanager_secret' pass arn error: Invalid template interpolation value
Terraform 'aws_secretsmanager_secret' pass arn error: Invalid template interpolation value
我有一个 Lambda,它会从 Secret Manager 读取一个秘密,它们都由 Terraform 管理。
所以在 Terraform 中我有这个秘密的定义:
resource "aws_secretsmanager_secret" "example" {
name = "example"
}
对于 Lambda,我已附加获取秘密的权限:
resource "aws_iam_role_policy" "example_role_policy" {
name = "example-role-policy"
role = aws_iam_role.example_lambda_role.id
policy = <<POLICY
{
"Version": "2012-10-17",
"Statement": [
{
.....(other needed permissions)
},
{
"Sid": "GetDatabaseSecret",
"Effect":"Allow",
"Action": [
"secretsmanager:GetSecretValue"
],
"Resource": "${local.secret_arn}"
}
]
}
POLICY
}
我在变量中定义了 secret_arn
:
locals{
secret_arn = "arn:aws:secretsmanager:::us-east-1:${local.account_number}:secret:${aws_secretsmanager_secret.example}-*"
}
当我应用 Terraform 时,出现错误:
Error: Invalid template interpolation value
on ..\..\xxx\terraform\variables.tf line 39, in locals:
39: secret_arn = "arn:aws:secretsmanager:::us-east-1:${local.account_number}:secret:${aws_secretsmanager_secret.example}-*"
|----------------
| aws_secretsmanager_secret.example is object with 12 attributes
Cannot include the given value in a string template: string required.
我尝试在 secrect_arn
中用 ??????
替换 *
但仍然无法正常工作,在网上找不到任何有用的东西,有人可以帮忙吗?非常感谢。
您的 local.secret_arn
应该使用 ${aws_secretsmanager_secret.example.name}-*"
,而不是 ${aws_secretsmanager_secret.example}-*"
。
但是最简单的方法将 arn 纳入您的保单中,它很简单:
resource "aws_iam_role_policy" "example_role_policy" {
name = "example-role-policy"
role = aws_iam_role.example_lambda_role.id
policy = <<POLICY
{
"Version": "2012-10-17",
"Statement": [
{
.....(other needed permissions)
},
{
"Sid": "GetDatabaseSecret",
"Effect":"Allow",
"Action": [
"secretsmanager:GetSecretValue"
],
"Resource": "${aws_secretsmanager_secret.example.arn}"
}
]
}
POLICY
}
我可能是错的,但我认为你想多了。
试试这个:
secret_arn = aws_secretsmanager_secret.example.arn
请记住,您在设置 AWS 提供商时设置了账户 ID 和区域:
provider "aws" {
alias = "ireland" # Your is in america but you get what I mean :)
version = "2.70.0"
region = "eu-west-1"
...
我有一个 Lambda,它会从 Secret Manager 读取一个秘密,它们都由 Terraform 管理。 所以在 Terraform 中我有这个秘密的定义:
resource "aws_secretsmanager_secret" "example" {
name = "example"
}
对于 Lambda,我已附加获取秘密的权限:
resource "aws_iam_role_policy" "example_role_policy" {
name = "example-role-policy"
role = aws_iam_role.example_lambda_role.id
policy = <<POLICY
{
"Version": "2012-10-17",
"Statement": [
{
.....(other needed permissions)
},
{
"Sid": "GetDatabaseSecret",
"Effect":"Allow",
"Action": [
"secretsmanager:GetSecretValue"
],
"Resource": "${local.secret_arn}"
}
]
}
POLICY
}
我在变量中定义了 secret_arn
:
locals{
secret_arn = "arn:aws:secretsmanager:::us-east-1:${local.account_number}:secret:${aws_secretsmanager_secret.example}-*"
}
当我应用 Terraform 时,出现错误:
Error: Invalid template interpolation value
on ..\..\xxx\terraform\variables.tf line 39, in locals:
39: secret_arn = "arn:aws:secretsmanager:::us-east-1:${local.account_number}:secret:${aws_secretsmanager_secret.example}-*"
|----------------
| aws_secretsmanager_secret.example is object with 12 attributes
Cannot include the given value in a string template: string required.
我尝试在 secrect_arn
中用 ??????
替换 *
但仍然无法正常工作,在网上找不到任何有用的东西,有人可以帮忙吗?非常感谢。
您的 local.secret_arn
应该使用 ${aws_secretsmanager_secret.example.name}-*"
,而不是 ${aws_secretsmanager_secret.example}-*"
。
但是最简单的方法将 arn 纳入您的保单中,它很简单:
resource "aws_iam_role_policy" "example_role_policy" {
name = "example-role-policy"
role = aws_iam_role.example_lambda_role.id
policy = <<POLICY
{
"Version": "2012-10-17",
"Statement": [
{
.....(other needed permissions)
},
{
"Sid": "GetDatabaseSecret",
"Effect":"Allow",
"Action": [
"secretsmanager:GetSecretValue"
],
"Resource": "${aws_secretsmanager_secret.example.arn}"
}
]
}
POLICY
}
我可能是错的,但我认为你想多了。 试试这个:
secret_arn = aws_secretsmanager_secret.example.arn
请记住,您在设置 AWS 提供商时设置了账户 ID 和区域:
provider "aws" {
alias = "ireland" # Your is in america but you get what I mean :)
version = "2.70.0"
region = "eu-west-1"
...