从字典中获取数据的更简单方法

Question

我有一本字典：元组的最后一个条目是射门的分钟数。例如：第90分钟巴西球员奥斯卡射门

players = {
    "Brazil": [
        (12, "Júlio César", "Goalkeeper", []),
        (4, "David Luiz", "Defender", []),
        (6, "Marcelo", "Defender", []),
        (13, "Dante", "Defender", []),
        (23, "Maicon", "Defender", []),
        (5, "Fernandinho", "Midfielder", []),
        (7, "Hulk", "Midfielder", []),
        (8, "Paulinho", "Midfielder", []),
        (11, "Oscar", "Midfielder", [90]),
        (16, "Ramires", "Midfielder", []),
        (17, "Luiz Gustavo", "Midfielder", []),
        (19, "Willian", "Midfielder", []),
        (9, "Fred", "Striker", []),
    ],
    "Germany": [
        (1, "Manuel Neuer", "Goalkeeper", []),
        (4, "Benedikt Höwedes", "Defender", []),
        (5, "Mats Hummels", "Defender", []),
        (16, "Philipp Lahm", "Defender", []),
        (17, "Per Mertesacker", "Defender", []),
        (20, "Jérôme Boateng", "Defender", []),
        (6, "Sami Khedira", "Midfielder", [29]),
        (7, "Bastian Schweinsteiger", "Midfielder", []),
        (8, "Mesut Özil", "Midfielder", []),
        (13, "Thomas Müller", "Midfielder", [11]),
        (14, "Julian Draxler", "Midfielder", []),
        (18, "Toni Kroos", "Midfielder", [24, 26]),
        (9, "André Schürrle", "Striker", [69, 79]),
        (11, "Miroslav Klose", "Striker", [23]),
    ],
}

我想创建一个函数，以球队和一分钟作为输入，returns那一分钟的进球数。我这样试过：

def score_at_minute(team,minute):
    global players
    goals = [goals for (number, player, position, goals) in players[team] if len(goals)>=1]
    goals_1 = [goal[0] for goal in goals if len(goal)>=1 if goal[0] <= minute]
    goals_2 = [goal[1] for goal in goals if len(goal) ==2 if goal[1]<= minute]
    all_goals = goals_1+goals_2
    return len(all_goals)

我的函数调用如下所示：

score_at_minute("Germany",90)

是否有更简单的方法或最好的方法是一个班轮？

Answer 1

这个怎么样-

def score_at_minute(x,y):
    return len([j for i in players.get(x) for j in i[3] if j<=y])

score_at_minute("Germany",25)

另一个版本-

score_at_minute = lambda x,y: len([j for i in players.get(x) for j in i[3] if j<=y])

score_at_minute('Germany', 90)

这是如何工作的 -

players.get(x) 获取国家 x
i[3] 是包含目标列表的项目
对此进行迭代时，您将得到一个列表列表，其中每个子列表都包含目标。 [[],[],[],[24],[32,45]] ..等等
您现在可以使用 [item for sublist in list for item in sublist]
然后您可以在此列表上应用过滤器（小于等于输入的分钟数）
最后计算长度。

Answer 2

您可以简单地使用列表理解

# For Germany
# For less than 90 minutes
len([eg for _,_,_,g in players['Germany'] for eg in g if eg<90])

Answer 3

使用items()

def score_at_minute(team,minute):        
    for key,val in players.items():
        if key==team:            
            return(len([j for i in val  for j in i[3] if j <=minute]))

从字典中获取数据的更简单方法

simpler way for getting data from dictionary

python

dictionary

list-comprehension

list

dictionary-comprehension