SPSS Loop：解析 n 个变量以获得值列表

Question

我想使用针列表遍历多个变量（即多个干草堆）。

数据：

PICK1	PICK2	PICK3	PICK4
Grape	Raspberry	Clementime	Strawberry
Strawberry	Lemon	Blueberry	Apple
Cantelope	Mango	Grape	Pear
Apple	Orange	Kiwi	Raspberry

有效的手动代码

Compute citrus=0
if char.index(PICK1,"orange")>0 citrus=1.
if char.index(PICK2,"orange")>0 citrus=1.
if char.index(PICK3,"orange")>0 citrus=1.
if char.index(PICK4,"orange")>0 citrus=1.
if char.index(PICK1,"lemon")>0 citrus=1.
if char.index(PICK2,"lemon")>0 citrus=1.
if char.index(PICK3,"lemon")>0 citrus=1.
if char.index(PICK4,"lemon")>0 citrus=1.
if char.index(PICK4,"clementine")>0 citrus=1.
if char.index(PICK4,"clementine")>0 citrus=1.
if char.index(PICK4,"clementine")>0 citrus=1.
if char.index(PICK4,"clementine")>0 citrus=1.

期望的结果：如果在变量中找到值，则记录 1

Citrus
1
1
0
1

尝试的代码（不工作）

do repeat L = [orange, lemon, clementine]
 /PICK = PICK1 to PICK7000.
compute L = if char.index(PICK,L)>0 citrus=1.
end repeat.

我最初使用 char.index 来搜索具有相似基本名称的多个值。例如，搜索“berry”会希望找到“strawberry”、“blueberry”等。有没有办法将其合并到 COMPUTE 函数中？

NUMERIC berry (f1.0).
DO REPEAT  PICK = PICK1 to PICK7000.
COMPUTE berry=any(PICK, char.index(PICK, "berry").
END REPEAT.
EXECUTE.

Answer 1

do repeat 结构使用长度必须相等的数组进行操作。最重要的是，您不需要方括号，并且在引号之间引用字符串。另外，不确定 compute 是否真的像那样工作，混合了 if 转换。

您想解析一个变量列表，检查 3 个字符串，并在满足条件时进行转换：

NUMERIC citrus (f1.0).
COMPUTE citrus=0.
DO REPEAT  PICK = PICK1 to PICK7000.
IF any(PICK, "orange", "lemon", "clementine") citrus=1.
END REPEAT.
EXECUTE.

或者，更合成一点：

NUMERIC citrus (f1.0).
DO REPEAT  PICK = PICK1 to PICK7000.
COMPUTE citrus=any(PICK, "orange", "lemon", "clementine").
END REPEAT.
EXECUTE.

或者，如果您还想查看任何“浆果”：

NUMERIC citrus (f1.0).
NUMERIC berries (f1.0).
DO REPEAT  PICK = PICK1 to PICK7000.
COMPUTE citrus=any(PICK, "orange", "lemon", "clementine").
COMPUTE berries = CHAR.INDEX(PICK, "berry")>0.
END REPEAT.
EXECUTE.

SPSS Loop：解析 n 个变量以获得值列表

SPSS Loop: parse n variables for list of values

loops

spss