为每个 id 生成日期系列

Question

我有一个包含四列的 table。我想为从 date1 到 date3 的每个 id 创建一个间隔为 1 天的日期列。如果没有date3那么到date2，如果没有date2，那么只有date1.

如何在 Postgres 中实现这一点？谢谢！

示例数据：

+-------+---------------------+---------------------+---------------------+
|  id   |        date1        |        date2        |        date3        |
+-------+---------------------+---------------------+---------------------+
| 76efg | 2021-01-03 06:33:54 | 2021-01-07 05:19:03 | 2021-01-08 05:19:03 |
| b67cs | 2021-01-09 03:45:24 | 2021-01-14 06:55:13 |                     |
| fsf56 | 2021-01-25 11:18:03 | 2021-01-25 11:18:03 |                     |
| ghl56 | 2021-01-29 14:25:57 | 2021-02-02 17:37:10 | 2021-02-18 01:13:37 |
| 90tum | 2021-02-18 06:13:30 |                     |                     |
+-------+---------------------+---------------------+---------------------+

id '76efg' 的期望输出：

+-------+--------------+---------------------+---------------------+---------------------+--+
|  id   | date_created |        date1        |        date2        |        date3        |  |
+-------+--------------+---------------------+---------------------+---------------------+--+
| 76efg | 2021-01-03   | 2021-01-03 06:33:54 | 2021-01-07 05:19:03 | 2021-01-08 05:19:03 |  |
| 76efg | 2021-01-04   | 2021-01-03 06:33:54 | 2021-01-07 05:19:03 | 2021-01-08 05:19:03 |  |
| 76efg | 2021-01-05   | 2021-01-03 06:33:54 | 2021-01-07 05:19:03 | 2021-01-08 05:19:03 |  |
| 76efg | 2021-01-06   | 2021-01-03 06:33:54 | 2021-01-07 05:19:03 | 2021-01-08 05:19:03 |  |
| 76efg | 2021-01-07   | 2021-01-03 06:33:54 | 2021-01-07 05:19:03 | 2021-01-08 05:19:03 |  |
| 76efg | 2021-01-08   | 2021-01-03 06:33:54 | 2021-01-07 05:19:03 | 2021-01-08 05:19:03 |  |
+-------+--------------+---------------------+---------------------+---------------------+--+

Answer 1

您是否尝试过使用 generated_series()? The following query generates a series of timestamps based on date1,date2 and date3, and the limit of the series found using COALESCE - 基本上检查列是否为 null .

WITH j (id,date1,date2,date3) AS (
  VALUES ('76efg',
          '2021-01-03 06:33:54'::TIMESTAMP,
          '2021-01-07 05:19:03'::TIMESTAMP,
          '2021-01-08 05:19:03'::TIMESTAMP ),
         ('b67cs',
         '2021-01-09 03:45:24'::TIMESTAMP,
         '2021-01-14 06:55:13'::TIMESTAMP,
         NULL),
         ('90tum','2021-02-18 06:13:30'::TIMESTAMP,
         NULL,NULL)
)
SELECT 
  id,
  generate_series(
    date1,
    COALESCE(date3,date2,date1),'1 day'::INTERVAL) AS date_created,
  date2,
  date3
FROM j;

  id   |    date_created     |        date2        |        date3        
-------+---------------------+---------------------+---------------------
 76efg | 2021-01-03 06:33:54 | 2021-01-07 05:19:03 | 2021-01-08 05:19:03
 76efg | 2021-01-04 06:33:54 | 2021-01-07 05:19:03 | 2021-01-08 05:19:03
 76efg | 2021-01-05 06:33:54 | 2021-01-07 05:19:03 | 2021-01-08 05:19:03
 76efg | 2021-01-06 06:33:54 | 2021-01-07 05:19:03 | 2021-01-08 05:19:03
 76efg | 2021-01-07 06:33:54 | 2021-01-07 05:19:03 | 2021-01-08 05:19:03
 b67cs | 2021-01-09 03:45:24 | 2021-01-14 06:55:13 | 
 b67cs | 2021-01-10 03:45:24 | 2021-01-14 06:55:13 | 
 b67cs | 2021-01-11 03:45:24 | 2021-01-14 06:55:13 | 
 b67cs | 2021-01-12 03:45:24 | 2021-01-14 06:55:13 | 
 b67cs | 2021-01-13 03:45:24 | 2021-01-14 06:55:13 | 
 b67cs | 2021-01-14 03:45:24 | 2021-01-14 06:55:13 | 
 90tum | 2021-02-18 06:13:30 |                     |

检查此 db<>fiddle。

感谢@clamp 关于 COALESCE:

的提示

COALESCE(COALESCE(date3,date2),date1) is equivalent to COALESCE(date3,date2,date1)

为每个 id 生成日期系列

Generate date series for each id

sql

postgresql

generate-series