干净的代码 - 使用具有特定规则的一个或多个过滤器搜索端点：如何避免多个 "ifs"？

Question

如果您开发的搜索端点可以有一个或多个过滤器，并且有组合这些过滤器的特定规则，如何避免使用多个“ifs”？

private void addCriteria(ProductFilter filter, Query query) {
//user does not fill anything, throws exception

        if (ObjectUtils.isEmpty(filter.getIds()) && !validateComboFilters(filter)) {
            throw new RequiredFilterException();
        }

//user does not fill id filter but fills other filters

        if (ObjectUtils.isEmpty(filter.getIds()) && validateComboFilters(filter)) {

            query.addCriteria(Criteria.where(Constants.CREATED_AT)
                    .gte(filter.getFromDate())
                    .lte(filter.getToDate()));

            query.addCriteria(Criteria.where(Constants.STATUS).in(filter.getStatus()));
        }

//user fills id filter and one or more other filters

        if (ObjectUtils.isNotEmpty(filter.getIds())) {

            query.addCriteria(Criteria.where(Constants.ID)
                    .is(filter.getIds()));

            if (filter.filterByRangeDate()) {
                query.addCriteria(Criteria.where(Constants.CREATED_AT)
                        .gte(filter.getFromDate())
                        .lte(filter.getToDate()));
            }
            if (filter.filterByStatus()) {
                query.addCriteria(Criteria.where(Constants.STATUS).in(filter.getStatus()));
            }
        }
    }

Answer 1

它可能看起来像这样。我没有检查编译，但我认为一般方法或多或少是正确的。

private static final BiFunction<ProductFilter, Query, Boolean> ADD_CRITERIA_IDS = (filter, query) -> {
    boolean res = ObjectUtils.isNotEmpty(filter.getIds());
    if (res)
        query.addCriteria(Criteria.where(Constants.ID).is(filter.getIds()));
    return res;
};

private static final BiFunction<ProductFilter, Query, Boolean> ADD_CRITERIA_STATUS = (filter, query) -> {
    boolean res = filter.filterByStatus();
    if (res)
        query.addCriteria(Criteria.where(Constants.STATUS).in(filter.getStatus()));
    return res;
};

private static final BiFunction<ProductFilter, Query, Boolean> ADD_CRITERIA_DATE_RANGE = (filter, query) -> {
    boolean res = filter.filterByRangeDate();
    if (res)
        query.addCriteria(Criteria.where(Constants.CREATED_AT)
                                  .gte(filter.getFromDate())
                                  .lte(filter.getToDate()));
    return res;
};

private void addCriteria(ProductFilter filter, Query query) {
    boolean added = ADD_CRITERIA_IDS.apply(filter, query);
    added |= ADD_CRITERIA_STATUS.apply(filter, query);
    added |= ADD_CRITERIA_DATE_RANGE.apply(filter, query);

    if (!added)
        throw new RequiredFilterException();
}

干净的代码 - 使用具有特定规则的一个或多个过滤器搜索端点：如何避免多个 "ifs"？

Clean code - Search endpoint with one or more filters with specific rules: How to avoid multiple "ifs"?

java

performance

spring

if-statement

coding-style