如何制作一个 python 文件副本，然后执行一次另一个副本？

Question

我正在使用 python 进行学校项目，我想知道如何创建具有这种效果的简单病毒

我试过这个： How do I use shutil to make a python file copy itself after doing a calculation?

还有这个：

然后我不知道如何运行第二个副本

代码示例（我想运行复制一次）

import os
import shutil

##############

print("hello world")

shutil.copy(__file__, "copy.py") # Copies the file
exec(open("copy.py").read())# Executes the copied file if it is in the same directory as the other file

Answer 1

您可以运行第二个文件 execfile(File Path)

所以你得到了类似

的东西

import os
import shutil
import fileinput

##############

print("hello world")

shutil.copy(__file__, "copy.py") # Copies the file

file = [Path of the copied File]    

for line in fileinput.FileInput(file, inplace=1):
    if "execfile('copy.py')" in line:
        line=line.rstrip()
        line=line.replace(line,"")
    print (line,end="")
# This could get a problem with large files but should work properly with small files

execfile('copy.py') # Executes the copied file if it is in the same directory as the other file
# Else give it the directory where the file is stored (with / instead of \)

Answer 2

所以我明白了（我也在reddit上发帖了）

link: https://www.reddit.com/r/learnpython/comments/lxupy9/how_to_make_a_python_file_copy_itself_then/

import shutil
import subprocess
import os
import random

print("hello world")
new_file_name = str(random.randint(1, 10000)) + ".py"
shutil.copy(__file__, new_file_name)

subprocess.call((new_file_name), shell=True)

如何制作一个 python 文件副本，然后执行一次另一个副本？

how to make a python file copy itself then execute the other copy once?

python

clone

virus