无论我将变量更改为 str 还是 int，终端都会给我一个语法错误

Question

我对运行代码在终端中不断收到的响应感到有些困惑。我正在制作一个具有简单输入界面的简单游戏，我想为玩家展示他们在该关卡中用完了多少次尝试。这是我的全部代码：

import random
import time

# I will fist make variables for the time breaks. S is for short, M is for medium and L is for long

S = 0.2
M = 0.7
L = 1.1

class Level_1_activated():

    def get_name(self):

        # This function simply asks the name of the player

        name = input("Before we start, what is your name? ")

        time.sleep(S)
        print("You said your name was: " + name)

    def try_again(self):

        # This asks the player if they want to try again, and shows the progress of the level
        
        answer = (input("Do you want to try again? "))
        time.sleep(M)

        if answer == "yes":
            print("Alright!, well I am going to guess that you want to play again")
            time.sleep(M)
            return True

        else:
            print("Thank you for playing the game, I hope you have better luck next time")
            # This is the return statement that stops the while loop 
            return False


    def find_rand_num(self, random):

        # This is the core of the level, where the player just chooses numbers between 1 and 10
        time.sleep(S)   

        print("The computer is choosing a random number between 1 and 10... beep beep boop")
        time.sleep(L)

        # The list of numbers for the level that the player is on at the moment
        num_list = [1,10]
        number = random.choice(num_list)

        ques = (input("guess your number, since this is the first level you need to choose a number between 1 and 10  "))
        print(ques)

        if ques == str(number):
            time.sleep(S)
            print("Congratulations! You got the number correct!")
            time.sleep(L)
            
            print("Good job! You will be progressing to the 2nd level now!")
            time.sleep(L*2)

            # Yet another return statement for the while loop
            return "Found"
            
        elif input != number:

            time.sleep(M)
            print("Oops, you got the number wrong")


def run_game():
    tries = 1
    while tries < 6:

        if tries < 2:
            Level_1_activated().get_name()
            print("You have used up " + tries + " of your tries already")
        
        res = Level_1_activated().find_rand_num(random)
        if res == "Found":
            break

        checker = Level_1_activated().try_again()
        if checker is False:
            break
        
        tries += 1
        print("Remember you have used up " + tries + " of your tries")

if __name__ == "__main__":
    run_game()

我会将代码缩小到我认为更相关的地方：

    tries = 1
    while tries < 6:

    if tries < 2:
        Level_1_activated().get_name()
        print("You have used up " + tries + " of your tries already")
    
    res = Level_1_activated().find_rand_num(random)
    if res == "Found":
        break

    checker = Level_1_activated().try_again()
    if checker is False:
        break
    
    tries += 1
    print("Remember you have used up " + tries + " of your tries")

if __name__ == "__main__":
    run_game()

我在这一行中遇到错误：

    print("Remember you have used up " + tries + " of your tries")

说的是：TypeError：只能将 str（不是“int”）连接到 str。我试过改

tries

至：

str(tries) or even int(tries)

我不确定如何解决这个问题。感谢您抽出宝贵时间，希望您能提供解决我错误的答案。

Answer 1

print("Remember you have used up {} of your tries".format(tries))
print("Remember you have used up {t} of your tries".format(t=tries))

您需要格式化字符串，将值传递给占位符。

Answer 2

当我在打印行中使用 str(tries) 时，它对我来说工作正常。

tries=10
print("Remember you have used up " + str(tries) + " of your tries")

输出

Remember you have used up 10 of your tries

能否请您再检查一次代码，我认为它应该可以正常工作。

无论我将变量更改为 str 还是 int，终端都会给我一个语法错误

No matter if I change my variable to str or int, terminal will give me a syntax error

python

string

integer