从数据框到矩阵列名的过去值(在 R 中)
past values from a data frame to column names of a matrix (in R)
我有一个数据框,行名称中包含单元格 ID,x 列中包含分类。
x
ACCTTAC do
ACCGTGG si
AGTCGGG si
我还有一个矩阵,其中列为细胞 ID,行为基因。
ACCTTAC ACCGTGG AGTCGGG
Gene1 4 5 1
Gene2 3 1 0
Gene3 3 3 1
我想粘贴来自数据框的矩阵分类的列名,请参见下面的示例。
do_ACCTTAC si_ACCGTGG si_AGTCGGG
Gene1 4 5 1
Gene2 3 1 0
Gene3 3 3 1
dput(df)
structure(list(x = c("do", "si", "si"), row.names = c("ACCTTAC", "ACCGTGG", "AGTCGGG"), class = "data.frame"))
mat = matrix(c(8,4,5,6,7,9,1,8,9),nrow = 3, ncol = 3,byrow = TRUE)
mat <- matrix(1:9, nrow = 3,dimnames = list(c("Gene1","Gene2","Gene3"), c("ACCTTAC","ACCGTGG","AGTCGGG")))
根据你的数据代码使用colnames和rownames:
dataframe <- data.frame(x = c("do", "si", "si"),
row.names = c("ACCTTAC", "ACCGTGG", "AGTCGGG"))
mat <- matrix(c(8,4,5,6,7,9,1,8,9),nrow = 3, ncol = 3,byrow = TRUE)
mat <- matrix(1:9, nrow = 3,dimnames = list(c("Gene1","Gene2","Gene3"),
c("ACCTTAC","ACCGTGG","AGTCGGG")))
dataframe$col_names <- row.names(dataframe)
for(i in 1:ncol(mat)) {
for(j in 1:nrow(dataframe)) {
if(row.names(dataframe)[j] == colnames(mat)[i])
colnames(mat)[i] = paste0(dataframe$x[j],"_",dataframe$col_names[j])
}
}
结果是:
> mat
do_ACCTTAC si_ACCGTGG si_AGTCGGG
Gene1 1 4 7
Gene2 2 5 8
Gene3 3 6 9
我有一个数据框,行名称中包含单元格 ID,x 列中包含分类。
x
ACCTTAC do
ACCGTGG si
AGTCGGG si
我还有一个矩阵,其中列为细胞 ID,行为基因。
ACCTTAC ACCGTGG AGTCGGG
Gene1 4 5 1
Gene2 3 1 0
Gene3 3 3 1
我想粘贴来自数据框的矩阵分类的列名,请参见下面的示例。
do_ACCTTAC si_ACCGTGG si_AGTCGGG
Gene1 4 5 1
Gene2 3 1 0
Gene3 3 3 1
dput(df)
structure(list(x = c("do", "si", "si"), row.names = c("ACCTTAC", "ACCGTGG", "AGTCGGG"), class = "data.frame"))
mat = matrix(c(8,4,5,6,7,9,1,8,9),nrow = 3, ncol = 3,byrow = TRUE)
mat <- matrix(1:9, nrow = 3,dimnames = list(c("Gene1","Gene2","Gene3"), c("ACCTTAC","ACCGTGG","AGTCGGG")))
根据你的数据代码使用colnames和rownames:
dataframe <- data.frame(x = c("do", "si", "si"),
row.names = c("ACCTTAC", "ACCGTGG", "AGTCGGG"))
mat <- matrix(c(8,4,5,6,7,9,1,8,9),nrow = 3, ncol = 3,byrow = TRUE)
mat <- matrix(1:9, nrow = 3,dimnames = list(c("Gene1","Gene2","Gene3"),
c("ACCTTAC","ACCGTGG","AGTCGGG")))
dataframe$col_names <- row.names(dataframe)
for(i in 1:ncol(mat)) {
for(j in 1:nrow(dataframe)) {
if(row.names(dataframe)[j] == colnames(mat)[i])
colnames(mat)[i] = paste0(dataframe$x[j],"_",dataframe$col_names[j])
}
}
结果是:
> mat
do_ACCTTAC si_ACCGTGG si_AGTCGGG
Gene1 1 4 7
Gene2 2 5 8
Gene3 3 6 9