如果列包含子字符串，phpmyadmin 会给出连接 2 个表的语法错误

Question

"mytest_people" 和 "mytest_hobbies":

  PK                 FK    <---  PK
+----+------+------+------+    +----+-----------------+
| Id | Name | Age  | H_ID |    | Id | Hobby           |
+----+------+------+------+    +----+-----------------+
| 0  | Pete | 100  | 0    |    | 0  | Reading News    |
| 1  | Mark | 5    | 1    |    | 1  | Reading Fiction |
| 2  | Bob  | 33   | 3    |    | 2  | Writing         |
| 3  | Lulu | 12   | 1    |    | 3  | Cooking         |
+----+------+------+------+    +----+-----------------+

这是我期望得到的：

+----+------+------+-----------------+
| Id | Name | Age  | Hobby           |
+----+------+------+-----------------+
| 0  | Pete | 100  | Reading News    |
| 1  | Mark | 5    | Reading Fiction |
| 3  | Lulu | 12   | Reading Fiction |
+----+------+------+-----------------+

这是日常用语/伪代码：

IN DATABASE "my_new_test_data_base"
SELECT COLUMNS "Id, Name, Age"
FROM TABLE "mytest_people"
WHERE COLUMN "H_ID"
    EQUALS COLUMN "Id"
    FROM TABLE "mytest_hobbies"
THEN JOIN COLUMN Hobby
FROM TABLE mytest_hobbies
ON CONDITION Hobby VALUES
    CONTAIN 'Reading%' SUBSTRING;

这是我对 SQL 代码的最新尝试：

USE my_new_test_data_base
SELECT mytest_people.Id, mytest_people.Name, mytest_people.Age FROM mytest_people
INNER JOIN mytest_hobbies (`Hobby`)
ON mytest_people.H_ID = mytest_hobbies.Id
WHERE `Hobby` LIKE 'Reading%';

这是我得到的错误：

#1064 - You have an error in your SQL syntax; check the manual that corresponds to your MariaDB server version for the right syntax to use near 'SELECT mytest_people.Id, mytest_people.Name, mytest_people.Age FROM mytest_peop' at line 2

Answer 1

一些小错误，每条命令都要以分号结束

别名不属于括号

USE my_new_test_data_base;
SELECT mytest_people.Id, mytest_people.Name, mytest_people.Age ,mytest_hobbies.`Hobby`
FROM mytest_people
INNER JOIN mytest_hobbies 
ON mytest_people.H_ID = mytest_hobbies.Id
WHERE mytest_hobbies.`Hobby` LIKE 'Reading%';

Answer 2

如果您喜欢少打字：

SELECT p.Id
     , p.Name
     , p.Age 
     , h.hobby
  FROM my_new_test_data_base.mytest_people p
  JOIN my_new_test_data_base.mytest_hobbies h
    ON p.H_ID = h.Id
 WHERE h.Hobby LIKE 'Reading%';

如果列包含子字符串，phpmyadmin 会给出连接 2 个表的语法错误

phpmyadmin gives syntax error to join 2 tables if a column contains substring

mysql

join

phpmyadmin

inner-join

syntax-error