Bazel $(location) 宏的绝对路径

Question

我正在使用 $(location) 将构建的 java_library 的位置传递给我的 java_binary（简化目标）：

java_binary(
    name = "my_bin",
    main_class = "Bin",
    srcs = [
        "Bin.java"
    ],
    deps = [
        ":my_lib"
    ],
    jvm_flags = [
        "-Dmy_library_path=$(location :my_lib)"
    ]
)

java_library(
    name = "my_lib",
    srcs = [
        "Lib.java"
    ]
)

看起来这个位置是相对于原始运行ning 位置的，这意味着当我在当前目录中使用 --run_under 到运行我的目标时，它会中断并且位置无效。

有没有办法获取绝对位置，或者有没有更便携的方法将 jar 路径传递给我的二进制文件？

Answer 1

写一个sh_binary to wrap it, and then use runfiles.bash在运行时查找路径。像这样（在将 my_bin 重命名为 my_bin_impl 并删除 jvm_flags 之后）：

sh_binary(
  name = "my_bin",
  srcs = [
    "my_bin_wrapper.sh",
  ],
  data = [
    ":my_bin_impl",
  ],
  deps = [
    "@bazel_tools//tools/bash/runfiles",
  ],
)

和 my_bin_wrapper.sh:

#!/bin/bash

# --- begin runfiles.bash initialization v2 ---
# Copy-pasted from the Bazel Bash runfiles library v2.
set -uo pipefail; f=bazel_tools/tools/bash/runfiles/runfiles.bash
source "${RUNFILES_DIR:-/dev/null}/$f" 2>/dev/null || \
  source "$(grep -sm1 "^$f " "${RUNFILES_MANIFEST_FILE:-/dev/null}" | cut -f2- -d' ')" 2>/dev/null || \
  source "[=11=].runfiles/$f" 2>/dev/null || \
  source "$(grep -sm1 "^$f " "[=11=].runfiles_manifest" | cut -f2- -d' ')" 2>/dev/null || \
  source "$(grep -sm1 "^$f " "[=11=].exe.runfiles_manifest" | cut -f2- -d' ')" 2>/dev/null || \
  { echo>&2 "ERROR: cannot find $f"; exit 1; }; f=; set -e
# --- end runfiles.bash initialization v2 ---

exec "$(rlocation "my_repository/my_package/my_bin_impl")" --jvm_flag=-Dmy_library_path="$(rlocation "my_repository/my_package/my_lib")" "$@"

如果你想像这样执行多个二进制文件，你可以包装生成包装器并在 macro.

中创建 sh_binary

Bazel $(location) 宏的绝对路径

Absolute path of Bazel $(location) macro

java

bazel