Hive 查询派生列并找到派生列的总数
Hive query for derived columns and find the total of derived column
我有一个场景,其中 credit_Date、debit_date 和 loan_date 可以相同。输出 table 有以下列
日期:应结合 credit_date、debit_date 和 loan_date(credit_date、debit_date 和 loan_date 可以相同(或)空)
Credit_payment: 计算给定 credit_date、实体、货币、所有者
的信用额度总和
Debit_payment: 计算给定 debit_date、实体、货币、所有者
的借方金额总和
Loan_payment: 求给定 loan_date、实体、货币、所有者
的贷款总额
实体: 来自 Table1
的值
货币: 值来自 Table 1
所有者: 值来自 Table 1
总计: (credit_payment + debit_payement+ loan_payment)
的总和
我试过下面的查询但没有用
insert into table2
select *
from (
select credit_date as date, sum(credit_amount) as credit_payment, null as debit_payment, null as loan_payment, entity, owner, currency
from table1
group by credit_date, entity, owner, currency
union all
select debit_date as date, null as credit_payment, sum(debit_amount) as debit_payment, null as loan_payment, entity, owner, currency
from table1
group by debit_date, entity,owner, currency
union all
select loan_date as date, null as credit_payment, null as debit_payment, sum(loan_amount) as loan_payment, entity, owner, currency
from table1
group by loan_date, entity, owner, currency
) t
order by date;
您可以使用coalesce
将group by前的三个日期组合起来。它将处理空值。
select coalesce(credit_date, debit_date, loan_date) as date,
sum(credit_amount) as credit_payment,
sum(debit_amount) as debit_payment,
sum(loan_amount) as loan_payment,
entity, currency, owner,
sum(credit_amount) + sum(debit_amount) + sum(loan_amount) as Total
from table1
group by coalesce(credit_date, debit_date, loan_date), entity, currency, owner
我有一个场景,其中 credit_Date、debit_date 和 loan_date 可以相同。输出 table 有以下列
日期:应结合 credit_date、debit_date 和 loan_date(credit_date、debit_date 和 loan_date 可以相同(或)空)
Credit_payment: 计算给定 credit_date、实体、货币、所有者
的信用额度总和Debit_payment: 计算给定 debit_date、实体、货币、所有者
的借方金额总和Loan_payment: 求给定 loan_date、实体、货币、所有者
的贷款总额实体: 来自 Table1
的值货币: 值来自 Table 1
所有者: 值来自 Table 1
总计: (credit_payment + debit_payement+ loan_payment)
的总和我试过下面的查询但没有用
insert into table2
select *
from (
select credit_date as date, sum(credit_amount) as credit_payment, null as debit_payment, null as loan_payment, entity, owner, currency
from table1
group by credit_date, entity, owner, currency
union all
select debit_date as date, null as credit_payment, sum(debit_amount) as debit_payment, null as loan_payment, entity, owner, currency
from table1
group by debit_date, entity,owner, currency
union all
select loan_date as date, null as credit_payment, null as debit_payment, sum(loan_amount) as loan_payment, entity, owner, currency
from table1
group by loan_date, entity, owner, currency
) t
order by date;
您可以使用coalesce
将group by前的三个日期组合起来。它将处理空值。
select coalesce(credit_date, debit_date, loan_date) as date,
sum(credit_amount) as credit_payment,
sum(debit_amount) as debit_payment,
sum(loan_amount) as loan_payment,
entity, currency, owner,
sum(credit_amount) + sum(debit_amount) + sum(loan_amount) as Total
from table1
group by coalesce(credit_date, debit_date, loan_date), entity, currency, owner