Table 行在 Oracle 中按月份汇总

Question

我有以下 Oracle table;

Site(VARCHAR2)	Product	Order Date(Date)	Quantity(Number)
A	X	3/5/2021 12:20:15 PM	100
B	Y	3/5/2021 12:20:15 PM	200
A	X	3/6/2021 12:20:15 PM	500
A	Z	3/6/2021 12:20:15 PM	400

我需要根据上面的内容生成类似于以下内容的摘要 table;

此处，为特定产品生成摘要以指示过去六个月的销售差价；

如何使用 Oracle SQL 实现这一点？

谢谢！

干杯，女弯

Answer 1

使用 SQL 编写查询时，您 select 必须知道这些列。但是，您不知道查询为运行时的最后六个月是什么时候。这意味着：您不能 select 名为 July 到 December 的列，因为查询可能会在 5 月得到运行。但是，您可以 select 称为“当前月份”、“上个月”等的列。

select
  sum(case when order_date >= trunc(sysdate, 'mm')
           and order_date < order_date >= trunc(sysdate, 'mm') + interval '1' month
           then quantity
      end) as "current month",
  sum(case when order_date >= trunc(sysdate, 'mm') - interval '1' month
           and order_date < order_date >= trunc(sysdate, 'mm')
           then quantity
      end) as "last month",
  sum(case when order_date >= trunc(sysdate, 'mm') - interval '2' month
           and order_date < order_date >= trunc(sysdate, 'mm') - interval '1' month
           then quantity
      end) as "current month minus 2",
  sum(case when order_date >= trunc(sysdate, 'mm') - interval '3' month
           and order_date < order_date >= trunc(sysdate, 'mm') - interval '2' month
           then quantity
      end) as "current month minus 3",
  sum(case when order_date >= trunc(sysdate, 'mm') - interval '4' month
           and order_date < order_date >= trunc(sysdate, 'mm') - interval '3' month
           then quantity
      end) as "current month minus 4",
  sum(case when order_date >= trunc(sysdate, 'mm') - interval '5' month
           and order_date < order_date >= trunc(sysdate, 'mm') - interval '4' month
           then quantity
      end) as "current month minus 5",
  sum(case when order_date >= trunc(sysdate, 'mm') - interval '5' month
           and order_date < order_date >= trunc(sysdate, 'mm') + interval '1' month
           then quantity
      end) as total
from mytable
group by site
order by site;

如果您想将此限制为一种产品，请添加 WHERE 子句。

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