如何获得彼此不同百分比的两个变量的不同结果

Question

我有一个包含不同事件的数据库，其中包括最大参与者数我有一个页面可以向人们展示我们有哪些活动，并且带有 link 到 inscripe 表单。所有事件的铭文都集中在同一个 table 中，其中有一列记录了它们所铭记的事件。ATM 显示有多少个地方以及已经有多少人订阅了。如果铭文数量等于参与者的最大数量，它也会阻止新的铭文。这看起来如下：

           <h2 class="title">
            <?php 
                           //display eventname
              $sql = "SELECT eventname FROM events WHERE id=1";    
              $data = $conn->query($sql);
              if ($data->num_rows > 0) {
                while($event = $data->fetch_assoc()) {
                  echo $event["eventname"];
                  $eventname = $event["eventname"];
                }
              } 
            ?> 
           </h2>

           <h2 style="color:red;"> 
              <?php 
                               //display registered participants
                $sql = ("SELECT COUNT(*) FROM eventregistrations WHERE eventname='$eventname'"); 
                $rs = mysqli_query($conn, $sql);
                $result = mysqli_fetch_array($rs);
                echo $result[0].'/'; 
                $numberparticipants = $result[0];

                          // display max participants
                $sql = "SELECT maxparticipants FROM events WHERE id=1";
                $result = $conn->query($sql);
                if ($result->num_rows > 0) {
                  while($row = $result->fetch_assoc()) {
                    echo $row["maxparticipants"];
                    $maxparticipants = $row["maxparticipants"];
                   }
                 } 
              ?> 
            </h2>

$numberparticipants 和 $maxparticipants 稍后用于将 link 更改为 inscripeform

我想要实现的是页面不显示确切的数字，而只显示活动的完整程度。像

      if ($numberparticipants < 80% of $maxparticipants) {
      echo 'free places';
      } else if ($numberparticipants BETWEEN 80% of $maxparticipants AND $maxparticipants ) {
      echo 'almost full';
      } else {
      echo 'full';
      }

谢谢博杰

Answer 1

为什么不像

$eightyPercent = intval(0.8 * $maxparticipants);
if($eightyPercent < $numberparticipants && $numberparticipants < $maxparticipants){
      echo 'almost full';
}

Answer 2

            $sql = ("SELECT COUNT(*) FROM registrations WHERE eventname='$eventname'"); 
            $rs = mysqli_query($conn, $sql);
            $result = mysqli_fetch_array($rs);
            $numberparticipants = $result[0];
            $sql = "SELECT maxparticipants FROM events WHERE id=1";
            $result = $conn->query($sql);
            if ($result->num_rows > 0) {while($row = $result->fetch_assoc()) {
                $maxparticipants = $row["maxparticipants"];}}
            $p80maxparticipants = ($maxparticipants *0.8);
            
            if ($numberparticipants < $p80maxparticipants) {
                echo 'Open for inscription';
            }else if ($numberparticipants >= $p80maxparticipants && $numberparticipants < $maxparticipants) {
                echo 'allmost full';
            }else if ($numberparticipants == $maxparticipants) {
                echo 'Volzet';
            }else{
                echo 'error';
            }

如何获得彼此不同百分比的两个变量的不同结果

How to get different outcomes of two variables being different percentage to eachother

php

percentage