XSLT

Question

对于下面的 XML，当字段 StartDate 不等于单元 5000 的任何 StartDate 项目时，我需要删除单元 6000 的所有 XML 个节点

我尝试匹配一个模板，但似乎匹配得很好

<?xml version="1.0" encoding="UTF-8"?>
<AllRecords>
   <Records>
      <Record>
         <Items>
            <EndDate>2021-03-31T00:00:00.000</EndDate>
            <PlantDetails>
               <PlantDetailsUS>
                  <company>1000</company>
                  <Newplant>TEST1</Newplant>
               </PlantDetailsUS>
            </PlantDetails>
            <StartDate>2021-01-01T00:00:00.000</StartDate>
            <Unit>5000</Unit>
            <Status>A</Status>
         </Items>
         <Items>
            <EndDate>2020-12-31T00:00:00.000</EndDate>
            <PlantDetails>
               <PlantDetailsUS>
                  <company>1000</company>
                  <Newplant>TEST2</Newplant>
               </PlantDetailsUS>
            </PlantDetails>
            <StartDate>2020-05-01T00:00:00.000</StartDate>
            <Unit>5000</Unit>
            <Status>A</Status>
         </Items>
         <Items>
            <EndDate>2021-02-31T00:00:00.000</EndDate>
            <PlantDetails>
               <PlantDetailsUS>
                  <company>1000</company>
                  <Newplant>TEST3</Newplant>
               </PlantDetailsUS>
            </PlantDetails>
            <StartDate>2021-02-01T00:00:00.000</StartDate>
            <Unit>5000</Unit>
            <Status>A</Status>
         </Items>
         <Items>
            <EndDate>2020-12-31T00:00:00.000</EndDate>
            <PlantDetails>
               <PlantDetailsUS>
                  <company>2000</company>
                  <Newplant>TEST4</Newplant>
               </PlantDetailsUS>
            </PlantDetails>
            <StartDate>2020-01-01T00:00:00.000</StartDate>
            <Unit>6000</Unit>
            <Status>A</Status>
         </Items>
         <Items>
            <EndDate>2021-03-31T00:00:00.000</EndDate>
            <PlantDetails>
               <PlantDetailsUS>
                  <company>2010</company>
                  <Newplant>TEST5</Newplant>
               </PlantDetailsUS>
            </PlantDetails>
            <StartDate>2021-01-01T00:00:00.000</StartDate>
            <Unit>6000</Unit>
            <Status>A</Status>
         </Items>
         <Items>
            <EndDate>2021-06-31T00:00:00.000</EndDate>
            <PlantDetails>
               <PlantDetailsUS>
                  <company>2020</company>
                  <Newplant>TEST5</Newplant>
               </PlantDetailsUS>
            </PlantDetails>
            <StartDate>2021-01-093T00:00:00.000</StartDate>
            <Unit>6000</Unit>
            <Status>A</Status>
         </Items>
      </Record>
   </Records>
</AllRecords>

xslt 代码

<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform" xmlns:xs="http://www.w3.org/2001/XMLSchema-instance">
    </xsl:stylesheet>
    <xsl:output method="xml" indent="yes"/>
    <xsl:strip-space elements="*" />
    <xsl:template match="@*|node()">
     <xsl:copy>
      <xsl:apply-templates select="@*|node()"/>
     </xsl:copy>
      </xsl:template>
    <xsl:variable name="date" select="xs:date(//Items[Status = 'A' and ( Unit=6000)) ]/StartDate
    <xsl:template match="$date eq xs:date(//Items[Status = 'A' and Unit='5000']/StartDate)"/>
    </xsl:stylesheet>

删除单元 6000 XML 节点后的预期输出 XSLT 代码，因为这 2 个节点的日期与 5000

的 xml 节点中的任何一个都不匹配

<?xml version="1.0" encoding="UTF-8"?>
<AllRecords>
   <Records>
      <Record>
         <Items>
            <EndDate>2021-03-31T00:00:00.000</EndDate>
            <PlantDetails>
               <PlantDetailsUS>
                  <company>1000</company>
                  <Newplant>TEST1</Newplant>
               </PlantDetailsUS>
            </PlantDetails>
            <StartDate>2021-01-01T00:00:00.000</StartDate>
            <Unit>5000</Unit>
            <Status>A</Status>
         </Items>
         <Items>
            <EndDate>2020-12-31T00:00:00.000</EndDate>
            <PlantDetails>
               <PlantDetailsUS>
                  <company>1000</company>
                  <Newplant>TEST2</Newplant>
               </PlantDetailsUS>
            </PlantDetails>
            <StartDate>2020-05-01T00:00:00.000</StartDate>
            <Unit>5000</Unit>
            <Status>A</Status>
         </Items>
         <Items>
            <EndDate>2021-02-31T00:00:00.000</EndDate>
            <PlantDetails>
               <PlantDetailsUS>
                  <company>1000</company>
                  <Newplant>TEST3</Newplant>
               </PlantDetailsUS>
            </PlantDetails>
            <StartDate>2021-01-01T00:00:00.000</StartDate>
            <Unit>5000</Unit>
            <Status>A</Status>
         </Items>
         <Items>
            <EndDate>2021-03-31T00:00:00.000</EndDate>
            <PlantDetails>
               <PlantDetailsUS>
                  <company>2010</company>
                  <Newplant>TEST5</Newplant>
               </PlantDetailsUS>
            </PlantDetails>
            <StartDate>2021-01-01T00:00:00.000</StartDate>
            <Unit>6000</Unit>
            <Status>A</Status>
         </Items>
      </Record>
   </Records>
</AllRecords>

Answer 1

delete all XML nodes of only Unit 6000 when field StartDate is not equal to any of the StartDate items of unit 5000

使用 key:

应该很容易实现

XSLT 1.0

<xsl:stylesheet version="1.0" 
xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output method="xml" version="1.0" encoding="UTF-8" indent="yes"/>
<xsl:strip-space elements="*"/>

<xsl:key name="k1" match="Items[Unit=5000]" use="StartDate" />

<!-- identity transform -->
<xsl:template match="@*|node()">
    <xsl:copy>
        <xsl:apply-templates select="@*|node()"/>
    </xsl:copy>
</xsl:template>

<!-- remove items that do not have a matching item -->
<xsl:template match="Items[Unit=6000][not(key('k1', StartDate))]"/>

</xsl:stylesheet>

Answer 2

此外 @micheal.hor257k good , this kind of problem can be easyly done with simple XPath/XSLT patterns:

<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform" version="1.0">  
  <xsl:output method="xml" indent="yes"/>  
  <xsl:strip-space elements="*"/>  
  <xsl:template match="@*|node()"> 
    <xsl:copy> 
      <xsl:apply-templates select="@*|node()"/> 
    </xsl:copy> 
  </xsl:template>  
  <xsl:template 
       match="Items[Unit=6000][not(StartDate = ../Items[Unit=5000]/StartDate)]"/> 
</xsl:stylesheet>

检查一下here

XSLT - 删除比较日期的 XML 个节点

XSLT - Delete XML nodes comparing dates

xslt-1.0

xslt-2.0