如何使用 criteriaBuilder 检查集合中的实体是否包含某个值?
How to check if entity in set contains a certain value using criteriaBuilder?
我有以下 类:
@Entity
public class Object {
@ManyToOne
@JoinColumn(name="RelationId", referencedColumnName = "ID", nullable=true)
private Relation relation;
}
@Entity
public class Relation{
@OneToMany(mappedBy="relation")
private Set<Object> objects = new HashSet<>();
@OneToMany(mappedBy="relation")
private Set<Contact> contactpersons = new HashSet<>();
}
@Entity
public class Contact{
@ManyToOne
@JoinColumn(name="RelationId")
private Relation relation;
private Boolean isPrimary;
}
这是我的 rootQuery 的一些代码:
private Stream<Specification<Object>> toSpec(List<SearchCriteria> searchCriteria){
return searchCriteria.stream().map(criteria ->{
if (criteria.isSet(ObjectKeys.searchObject)) {
return (Specification<Object>) (root, query, criteriaBuilder) -> {
List<Predicate> predicates = new ArrayList<>();
[Here a criteriabuilder predicate needs to go that check if object has relation that has
contacts that have isPrimary on true]
return criteriaBuilder.or(predicates.toArray(new Predicate[0]));
}
}
}
}
如何使用 criteriabuilder
检查对象的关系是否包含联系人 isPrimary
为真
我尝试使用 criteriaBuilder.in()
,但它只能检查联系人对象是否在集合中,而不能检查联系人对象是否具有特定值。我也尝试过使用联接来执行此操作,但这并没有给我正确的结果,因为我只能使用左联接、内联接或右联接,这会导致重复对象或不可空对象。
您在这里想要的是关系代数中所谓的半连接,它通过 SQL 中的 EXISTS 谓词建模并且在 JPA 中也受支持。您必须使用带有 exists 谓词的相关子查询。大致如下:
private Stream<Specification<Object>> toSpec(List<SearchCriteria> searchCriteria){
return searchCriteria.stream().map(criteria ->{
if (criteria.isSet(ObjectKeys.searchObject)) {
return (Specification<Object>) (root, query, criteriaBuilder) -> {
Subquery<Integer> subquery = query.subquery(Integer.class);
Root<Object> correlated = subquery.correlate(root);
Join<?, ?> join = correlated.join("relation").join("contactpersons");
subquery.select(criteriaBuilder.literal(1));
subquery.where(criteriaBuilder.isTrue(join.get("isPrimary")));
return criteriaBuilder.exists(subquery);
}
}
}
}
我有以下 类:
@Entity
public class Object {
@ManyToOne
@JoinColumn(name="RelationId", referencedColumnName = "ID", nullable=true)
private Relation relation;
}
@Entity
public class Relation{
@OneToMany(mappedBy="relation")
private Set<Object> objects = new HashSet<>();
@OneToMany(mappedBy="relation")
private Set<Contact> contactpersons = new HashSet<>();
}
@Entity
public class Contact{
@ManyToOne
@JoinColumn(name="RelationId")
private Relation relation;
private Boolean isPrimary;
}
这是我的 rootQuery 的一些代码:
private Stream<Specification<Object>> toSpec(List<SearchCriteria> searchCriteria){
return searchCriteria.stream().map(criteria ->{
if (criteria.isSet(ObjectKeys.searchObject)) {
return (Specification<Object>) (root, query, criteriaBuilder) -> {
List<Predicate> predicates = new ArrayList<>();
[Here a criteriabuilder predicate needs to go that check if object has relation that has
contacts that have isPrimary on true]
return criteriaBuilder.or(predicates.toArray(new Predicate[0]));
}
}
}
}
如何使用 criteriabuilder
检查对象的关系是否包含联系人isPrimary
为真
我尝试使用 criteriaBuilder.in()
,但它只能检查联系人对象是否在集合中,而不能检查联系人对象是否具有特定值。我也尝试过使用联接来执行此操作,但这并没有给我正确的结果,因为我只能使用左联接、内联接或右联接,这会导致重复对象或不可空对象。
您在这里想要的是关系代数中所谓的半连接,它通过 SQL 中的 EXISTS 谓词建模并且在 JPA 中也受支持。您必须使用带有 exists 谓词的相关子查询。大致如下:
private Stream<Specification<Object>> toSpec(List<SearchCriteria> searchCriteria){
return searchCriteria.stream().map(criteria ->{
if (criteria.isSet(ObjectKeys.searchObject)) {
return (Specification<Object>) (root, query, criteriaBuilder) -> {
Subquery<Integer> subquery = query.subquery(Integer.class);
Root<Object> correlated = subquery.correlate(root);
Join<?, ?> join = correlated.join("relation").join("contactpersons");
subquery.select(criteriaBuilder.literal(1));
subquery.where(criteriaBuilder.isTrue(join.get("isPrimary")));
return criteriaBuilder.exists(subquery);
}
}
}
}