如何按行获取列表中 str 项的所有组合 python

Question

我有一个 fasta 文件如下：

>seq1
AAAAAAAA
>seq2
TTTTTTTT
>seq3
CCCCCCCC
>seq4
GGGGGGGG

我想获得行的所有组合 (except the ones that start with > sign)。所需的输出应为：

AAAAAAAA
TTTTTTTT

AAAAAAAA
CCCCCCCC

AAAAAAAA
GGGGGGGG

TTTTTTTT
CCCCCCCC

TTTTTTTT
GGGGGGGG

CCCCCCCC
GGGGGGGG

我的代码在这里，但是缺少组合的最后一步：

from Bio import SeqIO

list1=[]
with open('file1.fa', 'r') as file1:
    for record1 in SeqIO.parse(file1, 'fasta'):
        list1.append(record1.seq)


for i in list1:
    print(i)

谢谢

Answer 1

尝试

from itertools import combinations as com

lst = ['A', 'B', 'C', 'D']
combi = list(com(lst, 2))

for entry in combi:
    print(entry[0])
    print(entry[1])
    print()

输出

A
B

A
C

A
D

B
C

B
D

C
D

如何按行获取列表中 str 项的所有组合 python

how to get all combinations of str items of a list row-wise python

python

list

itertools