井字游戏 - 无法分配给函数调用

Question

到目前为止，我正在 python 上制作井字游戏，我已经想出了一个非常可靠的代码，但我在某一点上遇到了一个我无法修复的错误。

代码如下：

from random import randint

List=[[0,0,0],[0,0,0],[0,0,0]]

def board(List):
    print('=== Tic Tac Toe ===')
    for i in range(3):
        print('   ',List[i][0],'  ',List[i][1],'   ',List[i][2])

def usr_choice(i,f,List):
    while List[i][f]!=0:
        i,f =eval(input('Please enter correct choice i or f: '))
    List[i][f]=2

def comp_choice(List):
    i=randint(0,2),f=randint(0,2)
    while List[i][f]!=0:
        i=randint(0,2),f=randint(0,2)
    List[i][f]=1
     
def decision(List):
    if [List[i][i] for i in range(3)]==[2,2,2] or \
        [List[2-i][i] for i in range(3)]==[2,2,2]: 
            print('You win!')
            return True
    elif[List[i][i] for i in range(3)]==[1,1,1] or \
        [List[2-i][i] for i in range(3)]==[1,1,1]: 
            print('You lose!')
            return True
    else: 
        for i in range(3):
            if [List [i][:]for i in range(3)]==[2,2,2] or \
                [List[f][i] for j in range(3)]==[2,2,2]:
                    print('You win!')
                    return True
            elif [List [i][:]for i in range(3)]==[1,1,1] or \
                [List[f][i] for j in range(3)]==[1,1,1]:
                    print('You lose!')
                    return True

这是我在 def comp_choice(List):

下收到的错误

 i=randint(0,2),j=randint(0,2)
   ^
SyntaxError: cannot assign to function call

Answer 1

要在同一赋值中声明多个变量，请执行：

i, j = randint(0, 2), randint(0, 2)

要在不同的赋值中但在同一行中声明多个变量，请执行：

i = randint(0, 2); j = randint(0, 2)

井字游戏 - 无法分配给函数调用

Tic Tac Toe Game- Can Not Assign to Function Call

python

syntax-error

tic-tac-toe