Python Pandas - 遍历 Excel 文件的文件夹，将数据从每个 Excel 文件的 sheet 导出到它们自己的 .xlsx 文件中

Question

我有一个包含 Excel 个文件的文件夹，其中许多文件包含 3-4 个标签的数据，我只希望将其作为单个 Excel 个文件。例如，假设我有一个包含三个选项卡的 Excel 文件：“employees”、“summary”和“data”。我希望由此创建 3 个新的 Excel 文件：employees.xlsx、summary.xlsx 和 data.xlsx.

我有代码可以遍历文件夹并识别所有选项卡，但我一直在努力弄清楚如何将数据从每个 sheet 单独导出到其自己的 Excel 文件中。我已经到了可以遍历文件夹、打开每个 Excel 文件并找到每个 sheet 的名称的地步。这是我目前所拥有的。

import pandas as pd
import os

# filenames
files = os.listdir()    
excel_names = list(filter(lambda f: f.endswith('.xlsx'), files))

excels = [pd.ExcelFile(name, engine='openpyxl') for name in excel_names]
sh = [x.sheet_names for x in excels] # I am getting all of the sheet names here
for s in sh:
    for x in s:
        #there is where I want to start exporting each sheet as its own spreadsheet

#df.to_excel("output.xlsx", header=False, index=False) #I want to eventually export it obviously, this is a placeholder

Answer 1

import pandas as pd
import glob

# get the file names using glob 
# (this assumes that the files are in the current working directory)
excel_names = glob.glob('*.xlsx')
# iterate through the excel file names
for excel in excel_names:
    # read the excel file with sheet_name as none
    # this will create a dict
    dfs = pd.read_excel(excel, sheet_name=None)
    # iterate over the dict keys (which is the sheet name)
    for key in dfs.keys():
        # use f-strings (only available in python 3) to assign 
        # the new file name as the sheet_name
        dfs[key].to_excel(f'{key}.xlsx', index=False)

Python Pandas - 遍历 Excel 文件的文件夹，将数据从每个 Excel 文件的 sheet 导出到它们自己的 .xlsx 文件中

Python Pandas - loop through folder of Excel files, export data from each Excel file's sheet into their own .xlsx file

python

excel

export-to-excel

dataframe

pandas