PHP 和 XAMPP 中的表单提交导致错误 404
Form submission results in Error 404 in PHP and XAMPP
所以,我是 PHP 的新手,主要问题是我在学习和听课,我完全按照讲师的要求做了,但是在展示我的代码之前我得到了不同的结果,这是我的项目目录:
这是我的代码:讲师说如果我们将 action = "" 留空,表单将由当前文件处理,这就是我想要做的。
<!DOCTYPE html>
<html lang="en">
<head>
<meta charset="UTF-8">
<meta http-equiv="X-UA-Compatible" content="IE=edge">
<meta name="viewport" content="width=device-width, initial-scale=1.0">
<title>PHP Form</title>
</head>
<body>
<h1>PHP Forms</h1>
<form action="get" method="" name="">
<label>Username:</label>
<input type = "text" name = "txtUsername" value = ""/>
<br/><br/>
<label>Email:</label>
<input type = "text" name = "txtUserEmail" value = ""/>
<br/><br/>
<label>List:</label>
<select name = "selMember">
<option value = "Please select">Please select</option>
<option value = "Joey">Joey</option>
<option value = "Rachel">Rachel</option>
<option value = "Chandler">Chandler</option>
<option value = "Monica">Monica</option>
<option value = "Phoebe">Phoebe</option>
<option value = "Ross">Ross</option>
</select>
<br/><br/>
<input type = "submit" value = "Submit" name = "subForm" />
</form>
<h2>User submitted data:</h2>
<?php
$username = $_GET['txtUsername'];
$userEmail = $_GET['txtUserEmail'];
$selectedMember = $_GET['selMember'];
echo "Username: $username <br/>";
echo "User's email: $userEmail <br/>";
echo "User's selected member: $selectedMember <br/>";
?>
</body>
</html>
所以这是表格:请忽略警告通知,因为讲师说他会在下一个视频中教如何处理它。
这是表单提交后的结果:
问题是表单被提交给这个URL:
"http://localhost:8080/php_code/get?txtUsername=anyone123&txtUserEmail=anyone%40gmail.com&selMember=Rachel&subForm=Submit
URL 应该提交给“http://localhost:8080/php_code/phpForms.php...”而不是“http://localhost:8080/ php_code/...".
所以,如果我手动输入正确的URL:
"http://localhost:8080/php_code/phpForms.php/get?txtUsername=anyone123&txtUserEmail=anyone%40gmail.com&selMember=Rachel&subForm=Submit",
表单提交就像讲师一样工作:
那么,我该如何解决这个问题呢?我是不是把文件放错了目录?
像这样更改您的表单标签。
<form action="" method="get" name="">
.......
</form>
所以,我是 PHP 的新手,主要问题是我在学习和听课,我完全按照讲师的要求做了,但是在展示我的代码之前我得到了不同的结果,这是我的项目目录:
这是我的代码:讲师说如果我们将 action = "" 留空,表单将由当前文件处理,这就是我想要做的。
<!DOCTYPE html>
<html lang="en">
<head>
<meta charset="UTF-8">
<meta http-equiv="X-UA-Compatible" content="IE=edge">
<meta name="viewport" content="width=device-width, initial-scale=1.0">
<title>PHP Form</title>
</head>
<body>
<h1>PHP Forms</h1>
<form action="get" method="" name="">
<label>Username:</label>
<input type = "text" name = "txtUsername" value = ""/>
<br/><br/>
<label>Email:</label>
<input type = "text" name = "txtUserEmail" value = ""/>
<br/><br/>
<label>List:</label>
<select name = "selMember">
<option value = "Please select">Please select</option>
<option value = "Joey">Joey</option>
<option value = "Rachel">Rachel</option>
<option value = "Chandler">Chandler</option>
<option value = "Monica">Monica</option>
<option value = "Phoebe">Phoebe</option>
<option value = "Ross">Ross</option>
</select>
<br/><br/>
<input type = "submit" value = "Submit" name = "subForm" />
</form>
<h2>User submitted data:</h2>
<?php
$username = $_GET['txtUsername'];
$userEmail = $_GET['txtUserEmail'];
$selectedMember = $_GET['selMember'];
echo "Username: $username <br/>";
echo "User's email: $userEmail <br/>";
echo "User's selected member: $selectedMember <br/>";
?>
</body>
</html>
所以这是表格:请忽略警告通知,因为讲师说他会在下一个视频中教如何处理它。
这是表单提交后的结果:
问题是表单被提交给这个URL: "http://localhost:8080/php_code/get?txtUsername=anyone123&txtUserEmail=anyone%40gmail.com&selMember=Rachel&subForm=Submit
URL 应该提交给“http://localhost:8080/php_code/phpForms.php...”而不是“http://localhost:8080/ php_code/...".
所以,如果我手动输入正确的URL:
"http://localhost:8080/php_code/phpForms.php/get?txtUsername=anyone123&txtUserEmail=anyone%40gmail.com&selMember=Rachel&subForm=Submit",
表单提交就像讲师一样工作:
那么,我该如何解决这个问题呢?我是不是把文件放错了目录?
像这样更改您的表单标签。
<form action="" method="get" name="">
.......
</form>