如何显示完整结果，而不是 python 中正则表达式搜索的匹配文本

Question

我正在创建一个基于关键字搜索文件的脚本，我的输出应该是整个观察结果，而不仅仅是匹配的文本，但我发现 .group 对此不起作用。

import re 
import os 
 
pers_info = pd.read_csv(r".....StateWorkforceMailingList_2-7-19a.csv",encoding='utf-8')

Pers_info['State'] = Texas, Florida etc... 

 files=os.listdir(r"....\State Files")
 
Files = list of WORKFORCE_2017_ALABAMA_FILE.xlsx,...,n

matches=re.findall(pers_info.State[4], files.replace("_", " "),re.I)
print(match)

我的预期输出是 WORKFORCE_2017_ALABAMA_FILE.xlsx 相反，我得到 'Alabama'

我应该尝试布尔掩码吗？

Answer 1

我想你的 Pers_info 看起来像这样：

Pers_info = {"state": ["Texas", "Alabama", "Florida"], "somethingelse": "stuff"}

你的文件是这样的：

files = ["WORKFORCE_2017_ALABAMA_FILE.xlsx","WORKFORCE_2017_TEXAS_FILE.xlsx","SOMETHING.xlsx"]

（你不需要正则表达式）

files = [file.lower() for file in files]
peers = [file.lower() for file in Pers_info['state']]
result = []

for x in peers:
    try:
        indx = peers.index(x)

        if any(peers[indx] in s for s in files):
            result.append(files[indx])
    except:
        break
print(result)

Answer 2

使用

>>> import pandas as pd
>>> Pers_info = pd.DataFrame({'State':['Texas', 'Alabama', 'Florida']})
>>> Files = ['WORKFORCE_2017_ALABAMA_FILE.xlsx', 'WORKFORCE_2017_FILE.xlsx']
>>> pattern = re.compile(rf'(?<![^\W_])(?:{"|".join(Pers_info["State"].to_list())})(?![^\W_])', re.I)
>>> list(filter(pattern.search, Files))
['WORKFORCE_2017_ALABAMA_FILE.xlsx']

参见regex proof。

解释

--------------------------------------------------------------------------------
  (?<!                     look behind to see if there is not:
--------------------------------------------------------------------------------
    [^\W_]                   any character except: non-word
                             characters (all but a-z, A-Z, 0-9, _),
                             '_'
--------------------------------------------------------------------------------
  )                        end of look-behind
--------------------------------------------------------------------------------
  (?:                      group, but do not capture:
--------------------------------------------------------------------------------
    Texas                    'Texas'
--------------------------------------------------------------------------------
   |                        OR
--------------------------------------------------------------------------------
    Alabama                  'Alabama'
--------------------------------------------------------------------------------
   |                        OR
--------------------------------------------------------------------------------
    Florida                  'Florida'
--------------------------------------------------------------------------------
  )                        end of grouping
--------------------------------------------------------------------------------
  (?!                      look ahead to see if there is not:
--------------------------------------------------------------------------------
    [^\W_]                   any character except: non-word
                             characters (all but a-z, A-Z, 0-9, _),
                             '_'
--------------------------------------------------------------------------------
  )                        end of look-ahead

如何显示完整结果，而不是 python 中正则表达式搜索的匹配文本

How to show full results, rather than matched text from regex searches in python

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