如何从中心点计算矩形的纬度和经度

Question

我想根据中心点 lat 和 lon 绘制一个矩形，假设给定的长度和宽度分别为 4.5m 和 1.5m。我想，我们也需要轴承。我通过在 Google 地球上绘制一个矩形进行模拟，获取位置并将它们放在我的代码中。但是，我需要一些自动的东西。我的问题是如何 link 以米为单位的那四个点（矩形）的笛卡尔坐标。

这是我的代码：

import geopandas as gpd
from shapely.geometry import Polygon

lat_point_list = [41.404928,  41.404936,  41.404951,  41.404943]
lon_point_list = [2.177339,   2.177331,   2.177353,   2.177365]

polygon_geom = Polygon(zip(lon_point_list, lat_point_list))
import folium
m = folium.Map([41.4049364, 2.1773560], zoom_start=20)
folium.GeoJson(polygon_geom).add_to(m)
folium.LatLngPopup().add_to(m)
m

我想要这个：

更新：

我知道这是基本的三角函数。如果我将矩形拆分成三角形，我们可以找到不同的点。我知道它是简单练习的基础，但是，我不知道它在使用笛卡尔坐标时会发生变化。然后，我的目标是得到点 A、B、C 和 D，知道矩形的中心经纬度、长度和宽度。

Answer 1

获取点的矩形（NE、SW）边界并将其用作 folium.Rectangle 的边界。

例如，使用您的数据。 4.5m和1.5m看矩形有点小：

import geopy
import geopy.distance
import math
import folium

def get_rectangle_bounds(coordinates, width, length):
    start = geopy.Point(coordinates)
    hypotenuse = math.hypot(width/1000, length/1000)

    # Edit used wrong formula to convert radians to degrees, use math builtin function
    northeast_angle = 0 - math.degrees(math.atan(width/length)) 
    southwest_angle = 180 - math.degrees(math.atan(width/length)) 

    d = geopy.distance.distance(kilometers=hypotenuse/2)
    northeast = d.destination(point=start, bearing=northeast_angle)
    southwest = d.destination(point=start, bearing=southwest_angle)
    bounds = []
    for point in [northeast, southwest]:
        coords = (point.latitude, point.longitude)
        bounds.append(coords)

    return bounds

# To get a rotated rectangle at a bearing, you need to get the points of the the recatangle at that bearing
def get_rotated_points(coordinates, bearing, width, length):
    start = geopy.Point(coordinates)
    width  = width/1000
    length = length/1000
    rectlength = geopy.distance.distance(kilometers=length)
    rectwidth = geopy.distance.distance(kilometers=width)
    halfwidth = geopy.distance.distance(kilometers=width/2)
    halflength = geopy.distance.distance(kilometers=length/2)

    pointAB = halflength.destination(point=start, bearing=bearing)
    pointA = halfwidth.destination(point=pointAB, bearing=0-bearing)
    pointB = rectwidth.destination(point=pointA, bearing=180-bearing)
    pointC = rectlength.destination(point=pointB, bearing=bearing-180)
    pointD = rectwidth.destination(point=pointC, bearing=0-bearing)

    points = []
    for point in [pointA, pointB, pointC, pointD]:
        coords = (point.latitude, point.longitude)
        points.append(coords)

    return points

start_coords = [41.4049364, 2.1773560]
length = 4.50 #in meters
width = 1.50
bearing = 45 #degrees

m = folium.Map(start_coords, zoom_start=20)
bounds = get_rectangle_bounds(tuple(start_coords),width, length )
points = get_rotated_points(tuple(start_coords), bearing, width, length)

folium.Rectangle(bounds=bounds,
                fill=True,
                color='orange',
                tooltip='this is Rectangle'
               ).add_to(m)

# To draw a rotated rectangle, use folium.Polygon
folium.Polygon(points).add_to(m)

如何从中心点计算矩形的纬度和经度

How to calculate lat and lon of a rectangle from a center point

dictionary

latitude-longitude

coordinates

shapely

folium