如何使用 GetX 更改 API link 保持相同的控制器和 UI
How to change API link keeping the same controller and UI using GetX
我有一个控制器,我在其中从 API 获取数据并添加到列表中
product_controller.dart
import 'package:get/state_manager.dart';
import 'package:get_it_test/services/product_services.dart';
class ProductController extends GetxController {
var ProductList = [].obs;
@override
void onInit() {
// TODO: implement onInit
fetchProduct();
super.onInit();
}
void fetchProduct() async {
var productsList = await ProductServices.fetchProducts();
//ProductServices is a Separate class from where I am fetching the API
print(productsList.data.products);
if (productsList != null) {
ProductList.assignAll(productsList.data.products);
}
}
}
我正在从 product_services.dart
获取数据
Product_services.dart
import 'package:get_it_test/Models/product_model.dart';
import 'package:http/http.dart' as http;
class ProductServices {
static var client = http.Client();
static Future fetchProducts() async {
var response = await client.post(
Uri.https('********.com', 'api/getProduct'),
//Here I want to change the number (4) to any other number to fetch different data
body:'{"category":"4","search":"","sortBy":"relavance","page":"","size":""}');
if (response.statusCode == 200) {
var jsonString = response.body;
print(productsScreenFromJson(jsonString));
return productsScreenFromJson(jsonString);
} else {
//show error message
return null;
}
}
}
我想通过单击 UI 屏幕上的另一个按钮更改 UI 中的数字来获取不同的数据。
我想保持控制器和 UI 屏幕相同,我只想根据按钮单击更改 API url 中的数字。
Productscreen.dart
import 'package:flutter/material.dart';
import 'package:get/get.dart';
import 'package:get_it_test/Views/Widgets/BottomBar.dart';
import 'package:cached_network_image/cached_network_image.dart';
import 'package:get_it_test/Controller/product_controller.dart';
import 'package:flutter_staggered_grid_view/flutter_staggered_grid_view.dart';
class ProductScreen extends StatelessWidget {
final String title;
ProductScreen(this.title);
final ProductController productController = Get.put(ProductController());
//I tried creating a constructor in the Controller and passing the data from here to the controller
//But I can only able to pass the hard code data through this as it is giving warning that
//access members can't be accessed through the initialiser
@override
Widget build(BuildContext context) {
return Scaffold(
appBar: AppBar(
iconTheme: IconThemeData(color: Colors.black),
backgroundColor: Colors.white,
title: Text(
title,
style: TextStyle(color: Colors.black),
),
),
body: SafeArea(
child: Column(
children: [
Expanded(
child: Obx(() => StaggeredGridView.countBuilder(
crossAxisCount: 2,
itemCount: productController.ProductList.length,
itemBuilder: (BuildContext context, int index) =>
new Container(
// height: 200,
width: 200,
child: Padding(
padding: const EdgeInsets.all(8.0),
child: Column(
children: [
CachedNetworkImage(
imageUrl: productController
.ProductList[index].image,
placeholder: (context, url) =>
new CircularProgressIndicator(),
errorWidget: (context, url, error) => new Image
.network(
'****.com/noimage.png'),
),
// Image.network(productController
// .ProductList[index].image),
Text(productController
.ProductList[index].prodName),
],
),
)),
staggeredTileBuilder: (int index) =>
new StaggeredTile.fit(1),
mainAxisSpacing: 4.0,
crossAxisSpacing: 4.0,
)),
),
BottomBar()
],
),
),
);
}
}
我尝试在控制器中创建构造函数并将数据从 ProductScreen.dart 页面传递到控制器
但我只能从这里传递硬代码数据,因为它发出警告
无法通过初始化程序访问实例成员变量
I hope you guys got my problem, I want the UI screen to be same and controller too. I only want to change the API link, which is fetching data from Product_Service.dart file and passing that data to the Controller inside the List.
static Future fetchProducts(int number) async {
var response = await client.post(
Uri.https('********.com', 'api/getProduct'),
//Here I want to change the number (4) to any other number to fetch different data
body:'{"category":"$number","search":"","sortBy":"relavance","page":"","size":""}');
.....
}
这不可能吗?
编辑
查看
Future getProductsWithAnotherCategory() async{
final ProductController productController = Get.put(ProductController());
final ProductController productController = Get.find();
await productController.fetchProducts(4);
}
这有帮助吗?
感谢@M.M.Hasibuzzaman的回答,我通过初始化解决了我的问题
final ProductController productController = Get.put(ProductController());
在 homepage.dart 文件中。
我在首页的onTap函数上传了Get.find<ProductController>().fetchProduct(3);
,让它传参
还在 ProductScreen.dart 文件中添加了 final ProductController productController = Get.find<ProductController>();
以便我可以在主页中使用相同的实例变量。它解决了我的问题。
我有一个控制器,我在其中从 API 获取数据并添加到列表中
product_controller.dart
import 'package:get/state_manager.dart';
import 'package:get_it_test/services/product_services.dart';
class ProductController extends GetxController {
var ProductList = [].obs;
@override
void onInit() {
// TODO: implement onInit
fetchProduct();
super.onInit();
}
void fetchProduct() async {
var productsList = await ProductServices.fetchProducts();
//ProductServices is a Separate class from where I am fetching the API
print(productsList.data.products);
if (productsList != null) {
ProductList.assignAll(productsList.data.products);
}
}
}
我正在从 product_services.dart
获取数据Product_services.dart
import 'package:get_it_test/Models/product_model.dart';
import 'package:http/http.dart' as http;
class ProductServices {
static var client = http.Client();
static Future fetchProducts() async {
var response = await client.post(
Uri.https('********.com', 'api/getProduct'),
//Here I want to change the number (4) to any other number to fetch different data
body:'{"category":"4","search":"","sortBy":"relavance","page":"","size":""}');
if (response.statusCode == 200) {
var jsonString = response.body;
print(productsScreenFromJson(jsonString));
return productsScreenFromJson(jsonString);
} else {
//show error message
return null;
}
}
}
我想通过单击 UI 屏幕上的另一个按钮更改 UI 中的数字来获取不同的数据。
我想保持控制器和 UI 屏幕相同,我只想根据按钮单击更改 API url 中的数字。
Productscreen.dart
import 'package:flutter/material.dart';
import 'package:get/get.dart';
import 'package:get_it_test/Views/Widgets/BottomBar.dart';
import 'package:cached_network_image/cached_network_image.dart';
import 'package:get_it_test/Controller/product_controller.dart';
import 'package:flutter_staggered_grid_view/flutter_staggered_grid_view.dart';
class ProductScreen extends StatelessWidget {
final String title;
ProductScreen(this.title);
final ProductController productController = Get.put(ProductController());
//I tried creating a constructor in the Controller and passing the data from here to the controller
//But I can only able to pass the hard code data through this as it is giving warning that
//access members can't be accessed through the initialiser
@override
Widget build(BuildContext context) {
return Scaffold(
appBar: AppBar(
iconTheme: IconThemeData(color: Colors.black),
backgroundColor: Colors.white,
title: Text(
title,
style: TextStyle(color: Colors.black),
),
),
body: SafeArea(
child: Column(
children: [
Expanded(
child: Obx(() => StaggeredGridView.countBuilder(
crossAxisCount: 2,
itemCount: productController.ProductList.length,
itemBuilder: (BuildContext context, int index) =>
new Container(
// height: 200,
width: 200,
child: Padding(
padding: const EdgeInsets.all(8.0),
child: Column(
children: [
CachedNetworkImage(
imageUrl: productController
.ProductList[index].image,
placeholder: (context, url) =>
new CircularProgressIndicator(),
errorWidget: (context, url, error) => new Image
.network(
'****.com/noimage.png'),
),
// Image.network(productController
// .ProductList[index].image),
Text(productController
.ProductList[index].prodName),
],
),
)),
staggeredTileBuilder: (int index) =>
new StaggeredTile.fit(1),
mainAxisSpacing: 4.0,
crossAxisSpacing: 4.0,
)),
),
BottomBar()
],
),
),
);
}
}
我尝试在控制器中创建构造函数并将数据从 ProductScreen.dart 页面传递到控制器 但我只能从这里传递硬代码数据,因为它发出警告 无法通过初始化程序访问实例成员变量
I hope you guys got my problem, I want the UI screen to be same and controller too. I only want to change the API link, which is fetching data from Product_Service.dart file and passing that data to the Controller inside the List.
static Future fetchProducts(int number) async {
var response = await client.post(
Uri.https('********.com', 'api/getProduct'),
//Here I want to change the number (4) to any other number to fetch different data
body:'{"category":"$number","search":"","sortBy":"relavance","page":"","size":""}');
.....
}
这不可能吗?
编辑 查看
Future getProductsWithAnotherCategory() async{
final ProductController productController = Get.put(ProductController());
final ProductController productController = Get.find();
await productController.fetchProducts(4);
}
这有帮助吗?
感谢@M.M.Hasibuzzaman的回答,我通过初始化解决了我的问题
final ProductController productController = Get.put(ProductController());
在 homepage.dart 文件中。
我在首页的onTap函数上传了Get.find<ProductController>().fetchProduct(3);
,让它传参
还在 ProductScreen.dart 文件中添加了 final ProductController productController = Get.find<ProductController>();
以便我可以在主页中使用相同的实例变量。它解决了我的问题。