TypeError: 'int' object is not subscriptable Genetic Algorithm with search
TypeError: 'int' object is not subscriptable Genetic Algorithm with search
我有这段代码,我正在尝试使用遗传算法进行本地搜索。我想将此数据用于 运行 到 :
[0 : [3,2,1],
1 : [4],
2 : [6,5],
3 : [7],
4 : [8],
5 : [9]]
这个想法是等于这个图(但用数字而不是字母):
这是我的代码:
import random
stringSize = 4
top = 10 * stringSize
def value(s):
return max(-abs(round(0.3*top) - s), .025 - abs(round(0.8 * top) - s))
def ga(times = 10, popSize = 20, mutation_prob = 0.001):
#population = [int(random.random() * top) for j in range(popSize)]
population = [0[3,2,1],
1[4],
2[6,5],
3[7],
4[8],
5[9]]
print(len(population))
print("---")
history = []
for i in range(times):
fitness = [value(population[j]) for j in range(popSize)]
fitMax = -float('inf')
for j in range(popSize):
if fitness[j] > fitMax:
fitMax = fitness[j]
jBest = j
history.append(population[jBest])
fit_sum = sum(fitness)
probs = [x/fit_sum for x in fitness]
cutoff = [sum(probs[:j+1]) for j in range(popSize)]
children = []
for j in range(popSize):
r = random.random()
for k in range(popSize):
if r < cutoff[k]:
break
par1 = population[k-1]
par2 = population[int(random.random() * popSize)]
split = int(random.random() * (stringSize + 1))
child = str(par1)[:split] + str(par2)[split:]
if random.random() < mutation_prob:
where = int(random.random() * stringSize)
what = str(int(random.random() * 10))
child = child[0:where] + what + child[where + 1:]
children.append(int(child))
population = children
return population
但是 运行它抛出这个错误:
TypeError Traceback (most recent call last)
<ipython-input-34-73e983c9ab93> in <module>()
----> 1 ga()
<ipython-input-33-a504bbf614a5> in ga(times, popSize, mutation_prob)
4 def ga(times = 10, popSize = 20, mutation_prob = 0.001):
5 #population = [int(random.random() * top) for j in range(popSize)]
----> 6 population = [0[3,2,1],
7 1[4],
8 2[6,5],
TypeError: 'int' object is not subscriptable
我该怎么做才能执行它?我做对了吗?
您的数组存在语义错误。例如。 1[2]
无效 python。如果你想做的是将一个数字映射到一个数字数组,请使用一个字典来索引每个列表或一个具有值和子属性的字典数组。
正如其他人已经指出的那样,您可以使用这样的字典:
population = {
0: [1,2],
1: [3,4,5],
...
}
您遇到的错误通常意味着您正在尝试索引一个无法索引的对象。
只需使用字典:
population = {0:[3,2,1],
1:[4],
2:[6,5],
3:[7],
4:[8],
5:[9]}
我有这段代码,我正在尝试使用遗传算法进行本地搜索。我想将此数据用于 运行 到 :
[0 : [3,2,1],
1 : [4],
2 : [6,5],
3 : [7],
4 : [8],
5 : [9]]
这个想法是等于这个图(但用数字而不是字母):
这是我的代码:
import random
stringSize = 4
top = 10 * stringSize
def value(s):
return max(-abs(round(0.3*top) - s), .025 - abs(round(0.8 * top) - s))
def ga(times = 10, popSize = 20, mutation_prob = 0.001):
#population = [int(random.random() * top) for j in range(popSize)]
population = [0[3,2,1],
1[4],
2[6,5],
3[7],
4[8],
5[9]]
print(len(population))
print("---")
history = []
for i in range(times):
fitness = [value(population[j]) for j in range(popSize)]
fitMax = -float('inf')
for j in range(popSize):
if fitness[j] > fitMax:
fitMax = fitness[j]
jBest = j
history.append(population[jBest])
fit_sum = sum(fitness)
probs = [x/fit_sum for x in fitness]
cutoff = [sum(probs[:j+1]) for j in range(popSize)]
children = []
for j in range(popSize):
r = random.random()
for k in range(popSize):
if r < cutoff[k]:
break
par1 = population[k-1]
par2 = population[int(random.random() * popSize)]
split = int(random.random() * (stringSize + 1))
child = str(par1)[:split] + str(par2)[split:]
if random.random() < mutation_prob:
where = int(random.random() * stringSize)
what = str(int(random.random() * 10))
child = child[0:where] + what + child[where + 1:]
children.append(int(child))
population = children
return population
但是 运行它抛出这个错误:
TypeError Traceback (most recent call last)
<ipython-input-34-73e983c9ab93> in <module>()
----> 1 ga()
<ipython-input-33-a504bbf614a5> in ga(times, popSize, mutation_prob)
4 def ga(times = 10, popSize = 20, mutation_prob = 0.001):
5 #population = [int(random.random() * top) for j in range(popSize)]
----> 6 population = [0[3,2,1],
7 1[4],
8 2[6,5],
TypeError: 'int' object is not subscriptable
我该怎么做才能执行它?我做对了吗?
您的数组存在语义错误。例如。 1[2]
无效 python。如果你想做的是将一个数字映射到一个数字数组,请使用一个字典来索引每个列表或一个具有值和子属性的字典数组。
正如其他人已经指出的那样,您可以使用这样的字典:
population = {
0: [1,2],
1: [3,4,5],
...
}
您遇到的错误通常意味着您正在尝试索引一个无法索引的对象。
只需使用字典:
population = {0:[3,2,1],
1:[4],
2:[6,5],
3:[7],
4:[8],
5:[9]}