如何在 C# 中完成一组任务后创建一个任务 运行?

How to make one task run after a collection of tasks has finished in C#?

我有一组任务必须在最后一个任务 运行 之前完成。具体来说:

protected override async Task ExecuteAsync(CancellationToken stoppingToken)
    {
        var task1 = Task.Run(() =>
        {
            Thread.Sleep(5000);
            Console.WriteLine("Task1");
        });

        var task2 = Task.Run(() =>
        {
            Thread.Sleep(5000);
            Console.WriteLine("Task2");
        });

        var task3 = Task.Run(() =>
        {
            Thread.Sleep(5000);
            Console.WriteLine("Task2");
        });

        var last = Task.Run(() =>
        {
            Console.WriteLine("Last");
        });

        var tasks = new List<Task>();
        tasks.Add(task1);
        tasks.Add(task2);
        tasks.Add(task3);

        await Task.WhenAll(tasks).ContinueWith(t => last);
    }

目前他们是这样完成的:

Last
Task2
Task3
Last1

我希望他们这样结束:

Task1
Task2
Task3
Last

前 3 个的顺序无关紧要,重要的是 最后 任务最后完成。 我不能阻塞线程或等待收集完成和类似的东西,只有 最后一个 任务必须在前三个完成后执行。

任务是“热”创建的,即已经在进行中。如果要延迟任务的开始,请使用委托 (Func<Task>) 或单独的 async 方法。

我喜欢这种行为的本地 async 方法:

protected override async Task ExecuteAsync(CancellationToken stoppingToken)
{
  async Task Task1() => Task.Run(() =>
  {
    Thread.Sleep(5000);
    Console.WriteLine("Task1");
  });

  async Task Task2() => Task.Run(() =>
  {
    Thread.Sleep(5000);
    Console.WriteLine("Task2");
  });

  async Task Task3() => Task.Run(() =>
  {
    Thread.Sleep(5000);
    Console.WriteLine("Task2");
  });

  async Task Last() => Task.Run(() =>
  {
    Console.WriteLine("Last");
  });

  var tasks = new List<Task>();
  tasks.Add(Task1());
  tasks.Add(Task2());
  tasks.Add(Task3());

  await Task.WhenAll(tasks);
  await Last();
}

P.S。 Don't use ContinueWith.

    //var last = Task.Run(() =>
    //{
    //    Console.WriteLine("Last");
    //});

    var tasks = new List<Task>();
    tasks.Add(task1);
    tasks.Add(task2);
    tasks.Add(task3);

    await Task.WhenAll(tasks);  //.ContinueWith(t => last);

    Task.Run(() =>
    {
        Console.WriteLine("Last");
    });