哪些运算符可用于整数除法？

Question

我在下面有这段代码，它假设生成 11 个矮人的输出，矮人身高输入 10，输入值 101、102、103、104,105、106、107、108、109 以及 110当矮人的高度再次为 10 时，巨大的高度然后变为 12 个矮人的输出，巨人高度的值为 111-120 等等。'n' 和 's' 具有基本相同的解决方案：正确的输出值 101 - 109 的小矮人，但对于值 110 的输出不正确（应该是 11，但给出 10）。可以使用哪些运算符来帮助解决这个问题。我正在研究我的运算符用法，强烈不希望使用任何条件语句或 if-then。

#include <stdio.h>

int main()
{
    int g, d, n, s;
    while(1)
    {
        printf("enter the heights of giant and drwafs: ");
        scanf("%d%d", &g, &d);
        
        n = g % d +  (g/d) + (-g % d + 1) - (g%d + 1)/10;
        s = g / d + 1;
        printf("%d",s);
        
        printf("it takes %d dwarfs to be "
               "greater than or equal to giant.\n\n", s );
    }
    
    return 0;
}

Answer 1

整数除法上限：

unsigned int dividend, divisor, c;
/* dividend != 0 && divisor != 0 */
c = 1 + ((dividend - 1) / divisor);

您的程序将如下所示：

#include <stdio.h>
#include <stdlib.h>

int main(void)
{
    unsigned int giant, dwarf, c;

    printf("Height of giant: ");
    scanf("%u", &giant);
    printf("Height of dwarf: ");
    scanf("%u", &dwarf);

    /* the heights can't be 0 */
    if (giant == 0 || dwarf == 0) {
        printf("The heights need to be greater than 0.\n");
        exit(EXIT_FAILURE);
    }

    /* ceil giant divided by dwarf */
    c = 1 + ((giant - 1) / dwarf);

    printf("It takes %u dwarfs to be as high "
           "or higher than a giant.\n", c);

    return 0;
}

Answer 2

您可以使用 NOT 运算符，如果您有余数则加 1，如果您没有余数则只是除法的结果：

include <stdio.h>

int main()
{
    int g, d, s;
    while(1)
    {
        printf("enter the heights of giant and drwafs: ");
        scanf("%d %d", &g, &d);
        if (d <= 0 || g <= 0) // what if your user use 0 for the size of dwarf? ouch...
            continue
        s = g / d + !!(g % d);
        printf("%d",s);
        
        printf("it takes %d dwarfs to be "
               "greater than or equal to giant.\n\n", s );
    }
    
    return 0;
}

注意：此解决方案适用于 giant = INT_MAX

哪些运算符可用于整数除法？

What operators can be used to ceil an integer division?

c

operators