R中数据帧中dput(head(data, 20))的输出

The output of dput(head(data, 20)) in data frame in R

我有一个如下所示的数据集 (name:data),其中包含多个国家/地区,在 3 列和 251453 行中的不同日期具有多种事件类型。我想计算每个国家/地区的每月事件。比如我想看《八月》中《也门》的《战役》有多少?我总共有 6 种不同的事件类型和 8 个不同的国家。

尽管花了好几个小时,但还是无法取得任何进展。感谢任何指导。

|event_date|        |event_type|                |country|
12 March 2021   Explosions/Remote violence;     Yemen;
12 March 2021   Explosions/Remote violence      Yemen
12 March 2021   Battles                         Afghanistan;
12 March 2021   Battles                         Afghanistan
12 March 2021   Protests                        Yemen 
12 March 2021   Protests                        Yemen

dput(样本)的输出

dput(head(data, 20))
structure(list(event_date = structure(c(420L, 420L, 420L, 420L, 
420L, 420L, 420L, 420L, 420L, 420L, 420L, 420L, 420L, 420L, 420L, 
420L, 420L, 420L, 420L, 420L), .Label = c("01 April 2018", "01 April 2019", 
"01 April 2020", "01 August 2018", "01 August 2019", "01 August 2020", 
"01 December 2018", "01 December 2019", "01 December 2020", "01 February 2019", 
    event_type = structure(c(2L, 2L, 1L, 1L, 3L, 3L, 3L, 3L, 
    4L, 1L, 1L, 3L, 4L, 3L, 1L, 1L, 4L, 6L, 6L, 3L), .Label = c("Battles", 
    "Explosions/Remote violence", "Protests", "Riots", "Strategic developments", 
    "Violence against civilians"), class = "factor"), country = structure(c(8L, 
    8L, 1L, 1L, 8L, 8L, 3L, 5L, 8L, 8L, 8L, 5L, 5L, 5L, 1L, 1L, 
    5L, 8L, 8L, 4L), .Label = c("Afghanistan", "Colombia", "India", 
    "Iraq", "Lebanon", "Libya", "Mali", "Yemen"), class = "factor")), row.names = c(NA, 
20L), class = "data.frame")
  

这可以用 aggregate 完成,只要日期是实际日期。

首先,将列 event_date 强制转换为 class "Date"

data$event_date <- as.Date(data$event_date, format = "%d %B %Y")

现在有两种方法,第一种不考虑年按月计算,第二种按年月计算。

month <- format(data$event_date, "%B")
aggregate(event_type ~ month + country, data, length)

yearmonth <- format(data$event_date, "%Y %B")
aggregate(event_type ~ yearmonth + country, data, length)