如何在选择不同的"difficulties"时弹出不同的消息？

Question

当我选择不同的“难度”并按下开始时，我希望得到不同的结果。我不能让它工作。我试图在 youtube 上寻找答案，但没有找到任何有用的信息。

import tkinter as tk
from tkinter import messagebox
import random

root = tk.Tk()

root.title("Simple Game")
canvas1 = tk.Canvas(root, width=300, height=300, bg="black")
canvas1.pack()
canvas1.create_text(150, 50, text="Simple Game", font="Times", fill="white")
root.resizable(False, False)

exitbutton = tk.Button(root, text="Exit Game", command=root.destroy, fg="black", activebackground="red").place(x=96,
                                                                                                               y=250)


def startgame():
    if DifficultyList == "Difficulty":
        messagebox.showinfo("Disclaimer", "You need to choose a difficulty!")
    elif DifficultyList == "Easy":
        messagebox.showinfo("Info", "You are now playing on Easy mode!")


startbutton = tk.Button(root, text="Start", command=startgame, fg="black", activeforeground="white",
                        activebackground="green").place(x=96, y=150)

canvas1.create_window(150, 150, window=exitbutton)
canvas1.create_window(150, 150, window=startbutton)

DifficultyList = (
    "Difficulty",
    "Easy",
    "Medium",
    "Hard"
)

variable = tk.StringVar(root)
variable.set(DifficultyList[0])

Difficulty = tk.OptionMenu(root, variable, *DifficultyList).place(x=94, y=100)

root.mainloop()

Answer 1

这是 tkinter 基础知识的一部分，您需要使用 get() 从 variable/radiobutton 中获取值，并将其与选项列表中的值进行核对（DifficultyList), 所以你的函数就像:

def startgame():
    if variable.get() == DifficultyList[1]: # Check if 2nd item on list is selected
        messagebox.showinfo("Info", "You are now playing on Easy mode!")
    elif variable.get() == DifficultyList[2]:
        messagebox.showinfo("Info", "You are now playing on Medium mode!")
    elif variable.get() == DifficultyList[3]:
        messagebox.showinfo("Info", "You are now playing on Hard mode!")
    else: # If the selection is anything else other than above mentioned, then
        messagebox.showinfo("Disclaimer", "You need to choose a difficulty!")

请注意我是如何更改您的 if 并将其移至 else，因为它是列表中唯一可供选择的语句，因此它是 else 的一部分。是的，你也可以选择任何其他语句作为 else，但这是唯一的奇数，所以我选择了这个。

请注意，虽然命名变量要遵循约定，例如列表通常会以所有小写字母命名，但 class 将按照 PascalCase and function might be named using camelCase but usual variables are all small letters. Also check: Some common naming conventions are for python

命名

如何在选择不同的"difficulties"时弹出不同的消息？

How do make different messages pop up when different "difficulties" are choosen?

python

variables

tkinter

drop-down-menu

options