更新 TABLE 计数

Question

我在更新时遇到了一些问题我在 informix 数据库中使用 posgress 我有两个 table.

1-st table with call data (anslogin, grade_1, grade_2, grade_3, grade_4, grade_5) 具有代理 ID 和每个代理的等级计数的第二数据按登录 ID 分组。我创建了 1-st table 并从 2-nd table.

复制了所有登录 ID

然后我想为每个年级 (1,2,3,4,5) 创建另外 5 个请求，但我在更新时遇到问题：

UPDATE grade a
    SET (grade_1) = (SELECT count(lastdigigts)
FROM call_rec b WHERE a.anslogin = b.anslogin
AND lastdigits ='1')

我不认为有五个请求的想法很好，但另一个我看不到的可能是你看到另一种解决我的任务的方法

tables 为了更好地理解：第一 table

| login | grade_1 | grade_2 | grade_3 | grade_4 | grade_5 |
| Ivan  |    2    |   3     |    4    |    1    |  null   |
| Masha |    1    |   3     |    4    |    null |  4      |
| Kolya |    5    |  null   |    4    |    1    |  null   |

第 2 table

|anslogin|lastfigits|
|Kolya   |       2  |
|Ivan    |       2  |
|Kolya   |       2  |
|Kolya   |       2  |
|Kolya   |       2  |
|Masha   |       2  |
|Ivan    |       2  |

Answer 1

如果我没理解错的话，你可以使用5个相关子查询：

UPDATE grade g
    SET grade_1 = (SELECT count(*) FROM call_rec cr WHERE g.anslogin = cr.anslogin AND lastdigits = '1'),
        grade_2 = (SELECT count(*) FROM call_rec cr WHERE g.anslogin = cr.anslogin AND lastdigits = '2'),
        grade_3 = (SELECT count(*) FROM call_rec cr WHERE g.anslogin = cr.anslogin AND lastdigits = '3'),
        grade_4 = (SELECT count(*) FROM call_rec cr WHERE g.anslogin = cr.anslogin AND lastdigits = '4'),
        grade_5 = (SELECT count(*) FROM call_rec cr WHERE g.anslogin = cr.anslogin AND lastdigits = '5');

请注意，我将 table 别名更改为有意义的缩写而不是任意字母。

在 Postgres 中，您可以将其简化为：

UPGRADE grade g
    SET grade_1 = cr.grade_1,
        grade_2 = cr.grade_2,
        grade_3 = cr.grade_3,
        grade_4 = cr.grade_4,
        grade_5 = cr.grade_5
    FROM (SELECT anslogin,
                 COUNT(*) FILTER (WHERE lastdigits = '1') as grade_1,
                 COUNT(*) FILTER (WHERE lastdigits = '2') as grade_2,
                 COUNT(*) FILTER (WHERE lastdigits = '3') as grade_3,
                 COUNT(*) FILTER (WHERE lastdigits = '4') as grade_4,
                 COUNT(*) FILTER (WHERE lastdigits = '5') as grade_5
          FROM call_rec cr
          GROUP BY anslogin
         ) cr
    WHERE cr.anslogin = g.anslogin;

Answer 2

此变体有效！！！

UPDATE grade g
    SET grade_1 = (SELECT count(*) FROM call_rec cr WHERE g.anslogin = r.anslogin AND lastdigits = '1'),
        grade_2 = (SELECT count(*) FROM call_rec cr WHERE g.anslogin = cr.anslogin AND lastdigits = '2'),
        grade_3 = (SELECT count(*) FROM call_rec cr WHERE g.anslogin = cr.anslogin AND lastdigits = '3'),
        grade_4 = (SELECT count(*) FROM call_rec cr WHERE g.anslogin = cr.anslogin AND lastdigits = '4'),
        grade_5 = (SELECT count(*) FROM call_rec cr WHERE g.anslogin = cr.anslogin AND lastdigits = '5');

Answer 3

可能有用。

UPDATE grade
    SET (grade_1,grade_2,grade_3,grade_4,grade_5) = (
    (
    SELECT 
    sum(case when lastdigits = '1' then 1 else 0 end) 
    ,sum(case when lastdigits = '2' then 1 else 0 end) 
    ,sum(case when lastdigits = '3' then 1 else 0 end) 
    ,sum(case when lastdigits = '4' then 1 else 0 end) 
    ,sum(case when lastdigits = '5' then 1 else 0 end) 
    FROM call_rec cr WHERE g.anslogin = r.anslogin
    )
);

更新 TABLE 计数

UPDATE TABLE with count

sql

informix

sql-update