如何在 UItableView 中按姓氏首字母将朋友分组
How to group friends by the first letter of the last name in UItableView into sections
我有朋友结构模型。
struct Friend {
let name: String
let photoImageName: String
}
还有我的 FriendsViewController 和 tableview outlet
final class FriendsViewController: UIViewController {
// MARK: - IBOutlet
@IBOutlet var tableView: UITableView!
// MARK: - Private Properties
private var friendsArray = [
Friend(name: "Donald Trump", photoImageName: "donald"),
Friend(name: "Mister Alan", photoImageName: "alan"),
Friend(name: "Eric Cartman", photoImageName: "cartman"),
Friend(name: "Tom Cruze", photoImageName: "cruze"),
]
// MARK: - Lifecycle
override func viewDidLoad() {
super.viewDidLoad()
// Do any additional setup after loading the view.
configureTable()
}
override func prepare(for segue: UIStoryboardSegue, sender: Any?) {
if segue.identifier == "GoToDetailPhoto" {
guard let destVC = segue.destination as? DetailPhotoCollectionViewController else { return }
if let indexPath = tableView.indexPathForSelectedRow {
let imageToTransfer = friendsArray[indexPath.row].photoImageName
destVC.imageName = imageToTransfer
}
}
}
// MARK: - Private methods
private func configureTable() {
tableView.dataSource = self
friendsArray.sort { [=11=].name < .name }
}
}
// MARK: - Table view data source
extension FriendsViewController: UITableViewDataSource {
func numberOfSections(in tableView: UITableView) -> Int {
1
}
func tableView(_ tableView: UITableView, numberOfRowsInSection section: Int) -> Int {
friendsArray.count
}
func tableView(_ tableView: UITableView, cellForRowAt indexPath: IndexPath) -> UITableViewCell {
guard let cell = tableView.dequeueReusableCell(
withIdentifier: FriendViewCell.identifier,
for: indexPath
) as? FriendViewCell else { return UITableViewCell() }
cell.configure(friend: friendsArray[indexPath.row])
return cell
}
}
如何按姓氏的首字母将它们分成不同的部分。就像在联系人应用程序中一样。谢谢你的回答。我想到了有字符的字典,但写不正确
在您的问题中,要获得唯一 surname/lastname 列表,您可以通过以下方式完成此操作:
let photoNameLetters = Set(friendsArray.map({ [=10=].photoImageName[[=10=].photoImageName.startIndex] }))
let lastNameLetters: Set<String> = Set(friendsArray.compactMap({
guard let lastName = [=10=].name.components(separatedBy: .whitespaces).last else { return nil }
return String(lastName[lastName.startIndex].lowercased())
}))
这应该可以解决问题。但是,它只会显示为“名称”属性 中的最后一个词。人们可以有带空格的姓氏。例如。 “范德维尔”或“维尔,范德”。
将数组更改为二维数组:
private var friendsArray = [
[Friend(name: "Donald Trump", photoImageName: "donald")],
[Friend(name: "Mister Alan", photoImageName: "alan")],
[Friend(name: "Eric Cartman", photoImageName: "cartman"),
Friend(name: "Tom Cruze", photoImageName: "cruze")],
]
func numberOfSections(in tableView: UITableView) -> Int {
filteredArrayOfGroups.count
}
func tableView(_ tableView: UITableView, numberOfRowsInSection section: Int) -> Int {
filteredArrayOfGroups[section].count
}
func tableView(_ tableView: UITableView, viewForHeaderInSection section: Int) -> UIView? {
let label = UILabel()
label.text = friendsArray[section][0].name.first?.description ?? ""
label.backgroundColor = UIColor.white.withAlphaComponent(0.5)
return label
}
我有朋友结构模型。
struct Friend {
let name: String
let photoImageName: String
}
还有我的 FriendsViewController 和 tableview outlet
final class FriendsViewController: UIViewController {
// MARK: - IBOutlet
@IBOutlet var tableView: UITableView!
// MARK: - Private Properties
private var friendsArray = [
Friend(name: "Donald Trump", photoImageName: "donald"),
Friend(name: "Mister Alan", photoImageName: "alan"),
Friend(name: "Eric Cartman", photoImageName: "cartman"),
Friend(name: "Tom Cruze", photoImageName: "cruze"),
]
// MARK: - Lifecycle
override func viewDidLoad() {
super.viewDidLoad()
// Do any additional setup after loading the view.
configureTable()
}
override func prepare(for segue: UIStoryboardSegue, sender: Any?) {
if segue.identifier == "GoToDetailPhoto" {
guard let destVC = segue.destination as? DetailPhotoCollectionViewController else { return }
if let indexPath = tableView.indexPathForSelectedRow {
let imageToTransfer = friendsArray[indexPath.row].photoImageName
destVC.imageName = imageToTransfer
}
}
}
// MARK: - Private methods
private func configureTable() {
tableView.dataSource = self
friendsArray.sort { [=11=].name < .name }
}
}
// MARK: - Table view data source
extension FriendsViewController: UITableViewDataSource {
func numberOfSections(in tableView: UITableView) -> Int {
1
}
func tableView(_ tableView: UITableView, numberOfRowsInSection section: Int) -> Int {
friendsArray.count
}
func tableView(_ tableView: UITableView, cellForRowAt indexPath: IndexPath) -> UITableViewCell {
guard let cell = tableView.dequeueReusableCell(
withIdentifier: FriendViewCell.identifier,
for: indexPath
) as? FriendViewCell else { return UITableViewCell() }
cell.configure(friend: friendsArray[indexPath.row])
return cell
}
}
如何按姓氏的首字母将它们分成不同的部分。就像在联系人应用程序中一样。谢谢你的回答。我想到了有字符的字典,但写不正确
在您的问题中,要获得唯一 surname/lastname 列表,您可以通过以下方式完成此操作:
let photoNameLetters = Set(friendsArray.map({ [=10=].photoImageName[[=10=].photoImageName.startIndex] }))
let lastNameLetters: Set<String> = Set(friendsArray.compactMap({
guard let lastName = [=10=].name.components(separatedBy: .whitespaces).last else { return nil }
return String(lastName[lastName.startIndex].lowercased())
}))
这应该可以解决问题。但是,它只会显示为“名称”属性 中的最后一个词。人们可以有带空格的姓氏。例如。 “范德维尔”或“维尔,范德”。
将数组更改为二维数组:
private var friendsArray = [
[Friend(name: "Donald Trump", photoImageName: "donald")],
[Friend(name: "Mister Alan", photoImageName: "alan")],
[Friend(name: "Eric Cartman", photoImageName: "cartman"),
Friend(name: "Tom Cruze", photoImageName: "cruze")],
]
func numberOfSections(in tableView: UITableView) -> Int {
filteredArrayOfGroups.count
}
func tableView(_ tableView: UITableView, numberOfRowsInSection section: Int) -> Int {
filteredArrayOfGroups[section].count
}
func tableView(_ tableView: UITableView, viewForHeaderInSection section: Int) -> UIView? {
let label = UILabel()
label.text = friendsArray[section][0].name.first?.description ?? ""
label.backgroundColor = UIColor.white.withAlphaComponent(0.5)
return label
}