Android HTTP 请求和响应

Question

我想在登录 Xamarin.Android 时从控制器发送一个 http post 请求。这是我来自 Login_Activity

的 C# 代码

btn_login_001.Click += (sender, e) =>{
    User user = new User(edit_user_001.Text.ToString(), edit_password_001.Text.ToString());
    User_controller user_controller = new User_controller();
    Task<HttpResponseMessage> response = user_controller.check_pass_void(user);

    switch (response.Status){
       case 200:
           Console.WriteLine("Status OK");
           break;
       case 404:
           Console.WriteLine("Status Not Found");
           break;
       default:
           Console.WriteLine("Status Other");
           break;
   }
};

此外，这是我来自控制器的代码

class User_controller {

  HttpClient client = new HttpClient();

  public async Task<HttpResponseMessage> check_pass_void(User user){

    try {
        Uri uri = new Uri("http://192.168.1.130:8080/noguiana/usuario/check_pass_void");

        // Convertir el usuario a JSON
        string user_json = JsonConvert.SerializeObject(user);
        StringContent content = new StringContent(user_json, Encoding.UTF8, "application/json");

        return await client.PostAsync(uri, content);

    } catch {
        return null;
    }

  } 
}

我的错误是 Task<HttpResponseMessage> 不是简单的 HttpResponseMessage。 Xamarin 使我转向 return Task<HttpResponseMessage>，现在我在使用 status 或取消我的 JSON 回复。

如果我施法，Task<HttpResponseMessage> response = user_controller.check_pass_void(user); 到 HttpResponseMessage response = (HttpResponseMessage)user_controller.check_pass_void(user); 它会给我这个按摩：

我能做什么？

Answer 1

你需要学会正确使用async/await

// mark the event handler as async
btn_login_001.Click += async (sender, e) =>{

   ...

   // check_pass_void() is async, so you need to await it
   HttpResponseMessage response = await user_controller.check_pass_void(user);

   ...

Android HTTP 请求和响应

Android HTTP request and response

android

http

response

request

xamarin