Jenkinsfile 打印参数很好

Question

我们有一个 Jenkinsfile，其参数声明如下：

def params = [string(name: 'ENVIRONMENT', value: environment),
              string(name: 'VERSION',     value: version),
              string(name: 'REGION',      value: region)]

我想回应这些，例如

DEPLOYING: ENVIRONMENT=STAGING, VERSION=1.3.0, REGION=EU

但是调用 echo "$params" 打印：

[@string(name=ENVIRONMENT,value=STAGING), @string(name=VERSION,value=1.3.0), @string(name=REGION,value=EU)]

我尝试迭代数组 - 例如:

params.each { echo it } 抛出 UnsupportedOperationException: no known implementation of class java.lang.String is using symbol ‘string’

params.each { echo it.name } 抛出 RejectedAccessException: No such field found: field org.jenkinsci.plugins.structs.describable.UninstantiatedDescribable name

我怎样才能很好地打印 params 数组？

编辑 - 来自 Matt Schuchard 的回复：

def params = [string(name: 'ENVIRONMENT', value: "STAGING"),
              string(name: 'VERSION',     value: "1.3.0"),
              string(name: 'REGION',      value: "EU")]
print "$params"

params.each() { param, value ->
    print "Parameter: ${param}, Value: ${value}"
}

returns（即值全为空）：

[@string(name=ENVIRONMENT,value=STAGING), @string(name=VERSION,value=1.3.0), @string(name=REGION,value=EU)]
Parameter: @string(name=ENVIRONMENT,value=STAGING), Value: null
Parameter: @string(name=VERSION,value=1.3.0), Value: null
Parameter: @string(name=REGION,value=EU), Value: null

Answer 1

您可以使用 Groovy 地图迭代器 lambda 方法（例如 each）迭代 params 地图。示例如下：

params.each() { param, value ->
  print "Parameter: ${param}, Value: ${value}"
}

如果您决定直接在 pipeline 块中使用它，那么在使用声明性 DSL 时需要将其放在 script 块中。

Answer 2

必须是更好的方法，但下面的方法有效

迭代参数数组：

 1. Cast each parameter to a regular String
 2. Extracted the value between @string( VALUE )
 3. Split the key/value pairs first by comma ','
 4. Then split each side of the above by equals '='
 5. Concatenate the second argument

def pretty(params) {
    def s = ""
    params.each { param ->
        def a = ("${param}" =~ /^@string\((.+)\)$/)[ 0 ][ 1 ]
        def b = a.split(",")
        s = s + b[0].split("=")[1] + "=" + b[1].split("=")[1] + "\n"
    }
    return s
}

Returns:

ENVIRONMENT=STAGING
VERSION=1.3.0
REGION=EU

Answer 3

是params目标是参数化构建吗？
如果是这种情况，您可以使用 parameters 指令

The parameters directive provides a list of parameters that a user should provide when triggering the Pipeline.
The values for these user-specified parameters are made available to Pipeline steps via the params object.

递减管道：

Declarative Pipeline supports parameters out-of-the-box, allowing the Pipeline to accept user-specified parameters at runtime via the parameters directive.

parameters {
        string(name: 'ENVIRONMENT', defaultValue: 'STAGING', description: 'Environment to test. e.g: production/develop'),
        string(name: 'VERSION', defaultValue: '1.3.0', description: 'Version to run'),
        string(name: 'REGION', defaultValue: 'EU', description: 'Region')
    }

脚本管道：

Configuring parameters with Scripted Pipeline is done with the properties step, which can be found in the Snippet Generator

properties([
    parameters([
        string(name: 'ENVIRONMENT', defaultValue: 'STAGING', description: 'Environment to test. e.g: production/develop'),
        string(name: 'VERSION', defaultValue: '1.3.0', description: 'Version to run'),
        string(name: 'REGION', defaultValue: 'EU', description: 'Region')
    ])
])

现在，这些参数可以作为 params 变量的成员访问
所以，那么你可以简单地使用：

params.each() { param, value ->
    print "Parameter: ${param}, Value: ${value}"
}

Jenkinsfile 打印参数很好

Jenkinsfile print parameters nicely

groovy

jenkins

jenkins-pipeline

hcl