如何在拖动鼠标时将绘制的形状绑定为正方形

Question

我在鼠标按下事件开始时绘制一个形状，该动画是在鼠标拖动事件上绘制的。下面是使用的代码：

override func mouseDown(with event: NSEvent) {

    self.startPoint = self.convert(event.locationInWindow, from: nil)
    if self.shapeLayer != nil {
        self.shapeLayer.removeFromSuperlayer()
        self.shapeLayer = nil
    }
    var pixelColor: NSColor = NSReadPixel(startPoint) ?? NSColor()
    shapeLayer = CAShapeLayer()
    shapeLayer.lineWidth = 1.0
    shapeLayer.fillColor = NSColor.clear.cgColor
    if pixelColor == NSColor.black {
        pixelColor = NSColor.color_white
    } else {
        pixelColor = NSColor.black
    }
    shapeLayer.strokeColor = pixelColor.cgColor
    shapeLayer.lineDashPattern = [1]
    self.layer?.addSublayer(shapeLayer)

    var dashAnimation = CABasicAnimation()
    dashAnimation = CABasicAnimation(keyPath: "lineDashPhase")
    dashAnimation.duration = 0.75
    dashAnimation.fromValue = 0.0
    dashAnimation.toValue = 15.0
    dashAnimation.repeatCount = 0.0
    shapeLayer.add(dashAnimation, forKey: "linePhase")
}

override func mouseDragged(with event: NSEvent) {
    let point: NSPoint = self.convert(event.locationInWindow, from: nil)
    let path = CGMutablePath()
    path.move(to: self.startPoint)
    path.addLine(to: NSPoint(x: self.startPoint.x, y: point.y))
    path.addLine(to: point)
    path.addLine(to: NSPoint(x: point.x, y: self.startPoint.y))
    path.closeSubpath()
    self.shapeLayer.path = path
}

目前它也会像这样绘制矩形：

我们能否将其绑定为正方形，以便当用户开始拖动鼠标时它将始终沿着正方形移动？

Answer 1

在 mouseDragged:

获取从startPoint.x到point.x
获取从startPoint.y到point.y
使用这两者的最大值或最小值（abs() 值）作为轮廓形状的宽度和高度

使用MAX会画出一个更大的正方形，当你穿过一个轴时它会“翻转”。使用 MIN 将绘制一个正方形，当您接近轴时该正方形会缩小到中心。查看差异的最简单方法是尝试一下：

var startPoint: CGPoint = .zero

override func mouseDown(with event: NSEvent) {
    self.startPoint = self.convert(event.locationInWindow, from: nil)
}

override func mouseDragged(with event: NSEvent) {
    let point: NSPoint = self.convert(event.locationInWindow, from: nil)

    var newPoint: CGPoint = self.startPoint
    
    let xDiff = point.x - self.startPoint.x
    let yDiff = point.y - self.startPoint.y
    
    // using min() will cause the square to "shrink"
    //  as you get closer to an axis
    let dist = min(abs(xDiff), abs(yDiff))
    
    // using max() will cause the square to "flip"
    //  when crossing an axis
    //let dist = max(abs(xDiff), abs(yDiff))
    
    newPoint.x += xDiff > 0 ? dist : -dist
    newPoint.y += yDiff > 0 ? dist : -dist
    
    let path = CGMutablePath()
    path.move(to: self.startPoint)
    path.addLine(to: NSPoint(x: self.startPoint.x, y: newPoint.y))
    path.addLine(to: newPoint)
    path.addLine(to: NSPoint(x: newPoint.x, y: self.startPoint.y))
    path.closeSubpath()
    self.shapeLayer.path = path
}

以防有人在 iOS 中寻找类似功能：

var startPoint: CGPoint = .zero

override func touchesBegan(_ touches: Set<UITouch>, with event: UIEvent?) {
    if let touch = touches.first {
        startPoint = touch.location(in: self)
    }
}

override func touchesMoved(_ touches: Set<UITouch>, with event: UIEvent?) {
    if let touch = touches.first {
        let point = touch.location(in: self)
        
        var newPoint: CGPoint = startPoint
        
        let xDiff = point.x - startPoint.x
        let yDiff = point.y - startPoint.y

        // using min() will cause the square to "shrink"
        //  as you get closer to an axis
        //let dist = min(abs(xDiff), abs(yDiff))
        
        // using max() will cause the square to "flip"
        //  when crossing an axis
        let dist = max(abs(xDiff), abs(yDiff))

        newPoint.x += xDiff > 0 ? dist : -dist
        newPoint.y += yDiff > 0 ? dist : -dist

        let path = CGMutablePath()
        path.move(to: startPoint)
        path.addLine(to: CGPoint(x: startPoint.x, y: newPoint.y))
        path.addLine(to: newPoint)
        path.addLine(to: CGPoint(x: newPoint.x, y: startPoint.y))
        path.closeSubpath()
        shapeLayer.path = path
    }
}

如何在拖动鼠标时将绘制的形状绑定为正方形

How to bound the drawn shape to square as mouse dragged

ios

swift

macos

crop

nsimage