我如何为此使用 zip 功能？

Question

for i in range(2200):
    calculate_path(r_mercury, mercury_track, i)
    calculate_path(r_venus, venus_track, i)
    calculate_path(r_earth, earth_track, i)
    calculate_path(r_mars, mars_track, i)
    calculate_path(r_jupiter, jupiter_track, i)
    calculate_path(r_saturn, saturn_track, i)
    calculate_path(r_uranus, uranus_track, i)
    calculate_path(r_neptune, neptune_track, i)

这是代码，我想用 zip 优化它，有什么办法可以做到吗？

而第一个 calculate_path的第一个参数是一个int，第二个是空列表，但我在函数中附加值。

Answer 1

我不会称之为优化，因为它不会改进任何东西，但这里有一个较短的实现：

r_planets = [r_mercury, r_venus, r_earth]
planets_tracks = [mercury_track, venus_track, earth_track]

for i in range(2200):
    for r_planet, planets_track in zip(r_planets, planets_tracks):
        calculate_path(r_planet, planets_track, i)

或者，少一个 for 循环（但迭代次数仍然相同）：

import itertools

r_planets = [r_mercury, r_venus, r_earth]
planets_tracks = [mercury_track, venus_track, earth_track]

for p, i in itertools.product(zip(r_planets, planets_tracks), range(2200)):
    r_planet = p[0] # can be remove
    planets_track = p[1] # can be remove
    calculate_path(r_planet, planets_track, i) # can be replace with calculate_path(p[0], p[1], i)

我如何为此使用 zip 功能？

How can I use zip function for this?

python

zip