最好使用语法或正则表达式解析 table

Question

有几天我卡住了；我想解析一个包含许多页面的大型文档，其中包含 table 像这样的内容：

                Col1  Col2  Col3   Col4

                TXT1       TTT     Fnam1, LNam1

                TXT2       TEE     Fnam2, Mnam LNam2

                TXT1

                TXT5       ART     Fnam3, LNam3

                     TXT6  BGT     Fnam4, LNam4

我已经用琶音编写了语法 (python) 如果所有单元格都不为空，我可以解析 table 但如果有一个或多个空单元格，一切都会成为一部分。任何人都知道我如何在不使用歧义语法的情况下做到这一点？提前致谢

Answer 1

感谢@JeffC 的提示，我通过询问空格数找到了解决方案。这是语法：

from __future__ import print_function, unicode_literals

import os
from arpeggio import ParserPython
from arpeggio import Optional, ZeroOrMore, OneOrMore, EOF,  PTNodeVisitor, ParserPython, visit_parse_tree, Combine
from arpeggio.export import PMDOTExporter, PTDOTExporter
from arpeggio import RegExMatch as _


def wsx() : return _(r"[ \t]*")
def ws2() : return _(r"[ \t]{2}")
def ws16() : return _(r"[ \t]{16}")
def code(): return _(r"[a-zA-Z0-9]{2,}")
def col4_title(): return "Col4"
def col3_title(): return "Col3"
def col2_title(): return "Col2"
def col1_title(): return "Col1"
def cell_col4(): return [Combine(wsx,OneOrMore(word,Optional(ws2)),Optional(",", OneOrMore(ws2,word))),wsx]
def cell_col3(): return [code,wsx]
def cell_col2(): return [code,wsx]
def cell_col1(): return [code,wsx]
def team_row(): return ws16, Optional(cell_col1),Optional(ws2),Optional(cell_col2),Optional(ws2),Optional(cell_col3),Optional(ws2),Optional(cell_col4),Optional(wsx), nl
def team_table_body(): return wsx, OneOrMore(nl,team_row),
def team_table_title(): return "testtab"
def team_table_header(): return wsx, team_table_title, wsx, col1_title, wsx, col2_title, wsx, col3_title, wsx, col4_title,Optional(wsx),nl
def team_block(): return wsx, team_table_header, team_table_body

最好使用语法或正则表达式解析 table

Parsing a table using preferably grammar or regex

python

regex

grammar

parsing

peg