对于零件级别为 0 的同一零件，如何获取具有映射到和没有映射的零件 ID？

Question

如何获取零件级别为 0 而没有贴图的零件 ID？

我使用 SQL Server 2012 并面临这样的问题，即对于零件级别为 0 的同一零件，我无法获得具有映射到和没有映射的零件。

如果零件的代码类型为 1273200，则零件级别 0 的代码类型必须为 974451。
如果零件的代码类型为 194480，则零件级别 0 的代码类型必须为 7320911。

所以我需要显示：

代码类型为 1273200 的部件
零件级别 0 且没有来自 974451 的地图

或

代码类型为 194480 的部件
零件级别 0 且没有来自 7320911 的地图

代码：

create table #codes
(
    PartId int,
    CodeTypeId  int,
    Partlevel int
)

insert into #codes (PartId, CodeTypeId, Partlevel)
values
    ---this is correct----
    (1250, 974451, 0),  ---map from
    (1250, 1273200, 0), ---map to
    (1250, 7320911, 0), ---map from
    (1250, 194480, 0),  --map to
    ------------------
    --where map from 974451 for part id 1900 for partlevel 0
    (1900, 1273200, 0),---map to
    (1900, 7320911, 0),---map from
    (1900, 194480, 0),--map to
    ------------------
    (2200, 974451, 0),---map from
    (2200, 1273200, 0),---map to
    --where map from 7320911 for part id 2200 for partlevel 0
    (2200, 194480, 0),--map to
    -----------------
    (3400, 974451, 1),  --where map from 974451 for part id 3400 for partlevel 0 so if 1 it is wrong
    (3400, 1273200, 0), ---map to
    (3400, 7320911, 0), ---map from
    (3400, 194480, 0),  --map to
    -----------------
  --where map from 974451 for part id 3900 for partlevel 0 so if 1 then it is not exist 
   (3900, 1273200, 0), ---map to
   (3900, 1997801, 0), 
   (3900, 7320911, 0), ---map from
   (3900, 194480, 0),  --map to
   ---------------   
   (5020, 974451, 1), 
   (5020, 1997801, 1),
   (5020, 7320911, 1), --where map from 7320911 for part id 5020 for partlevel 0 if 1 then it is not exist
   (5020, 194480, 0),  --map to
   ------------------
   ---map from 974451 not exist for part id 7050 but not care because I need only parts have partlevel 0
 (7050,1273200,1), ---map to
 (7050,7320911,1), ---map from
 (7050,194480,1),  --map to
 -----------------
  ---map from 7320911 not exist for part id 8900 for partlevel 0 if part level 1 then not exist 
 (8900,7320911,1), ---map from
 (8900,194480,0),  --map to
 -----------------
    
  ---map from 7320911 not exist for part id 9200 for partlevel 0  
 (9200,194480,0)  --map to
 -----------------

我尝试的是

select partid,codetypeid from #codes
where partlevel=0 and codetypeid=974451 and codetypeid <> 1273200
group by partid,codetypeid

union all

select partid,codetypeid from #codes
where partlevel=0 and codetypeid=194480 and codetypeid <> 7320911
group by partid,codetypeid

正确的结果必须如下：

Answer 1

解决方案

Select 行（c1）在第 0 级...
c1.PartLevel = 0
... 并筛选 to 行。
c1.CodeTypeId in (194480, 1273200)
对应行(c2)...
where c2.PartId = c1.PartId and c2.PartLevel = c1.PartLevel
...必须丢失...
where not exists (...)
...链接到固定的 from/to 对。
and (c1.CodeTypeId <> 1273200 or c2.CodeTypeId = 974451)
and (c1.CodeTypeId <> 194480 or c2.CodeTypeId = 7320911)

第 5 步在伪代码中转换为以下内容：

if (c1.CodeTypeId = 1273200)
{
  c2.CodeTypeId = 974451;
}
if (c1.CodeTypeId = 194480)
{
  c2.CodeTypeId = 7320911;
}

结合一切：

select c1.PartId,
       c1.CodeTypeId,
       c1.PartLevel
from codes c1
where c1.PartLevel = 0
  and c1.CodeTypeId in (194480, 1273200) -- "to"
  and not exists ( select 'x'
                   from codes c2
                   where c2.PartId = c1.PartId
                     and c2.PartLevel = c1.PartLevel
                     and (c1.CodeTypeId <> 1273200 or c2.CodeTypeId =  974451)    -- "from" v1
                     and (c1.CodeTypeId <>  194480 or c2.CodeTypeId = 7320911) ); -- "from" v2

结果

PartId  CodeTypeId  PartLevel
------  ----------  ---------
1900    1273200     0
2200    194480      0
3400    1273200     0
3900    1273200     0
5020    194480      0
8900    194480      0
9200    194480      0

Fiddle 查看所有内容。

对于零件级别为 0 的同一零件，如何获取具有映射到和没有映射的零件 ID？

How to get Part Id that have map to and not have map from for same part where part level 0?

tsql

sql-server

stored-procedures

sql-function

sql-server-2012