Converting A List of MediaItem to ConcatenatingAudioSource Error: Instance of 'ConcatenatingAudioSource'
Converting A List of MediaItem to ConcatenatingAudioSource Error: Instance of 'ConcatenatingAudioSource'
我正在尝试 parse/convert MediaItem
列表到 ConcatenatingAudioSource
,但我的单元测试一直给我一个错误,即转换后的 ConcatenatingAudioSource
不匹配了解目标来源。我的测试是
List<MediaItem> audioSource = <MediaItem>[
MediaItem(
// This can be any unique id, but we use the audio URL for convenience.
id: "https://s3.amazonaws.com/scifri-episodes/scifri20181123-episode.mp3",
album: "Science Friday",
title: "A Salute To Head-Scratching Science",
artist: "Science Friday and WNYC Studios",
duration: Duration(milliseconds: 5739820),
artUri: Uri.parse(
"https://media.wnyc.org/i/1400/1400/l/80/1/ScienceFriday_WNYCStudios_1400.jpg"),
),
MediaItem(
id: "https://s3.amazonaws.com/scifri-segments/scifri201711241.mp3",
album: "Science Friday",
title: "From Cat Rheology To Operatic Incompetence",
artist: "Science Friday and WNYC Studios",
duration: Duration(milliseconds: 2856950),
artUri: Uri.parse(
"https://media.wnyc.org/i/1400/1400/l/80/1/ScienceFriday_WNYCStudios_1400.jpg"),
),
];
test('mediaItem2ConcatenatingAudioSource test', () {
expect(
// Here's where the conversion happens
ConcatenatingAudioSource(
children: audioSource
.map((item) => AudioSource.uri(Uri.parse(item.id)))
.toList(),
),
ConcatenatingAudioSource(children: [
AudioSource.uri(Uri.parse(
'https://s3.amazonaws.com/scifri-episodes/scifri20181123-episode.mp3')),
AudioSource.uri(Uri.parse(
"https://s3.amazonaws.com/scifri-segments/scifri201711241.mp3")),
]),
);
});
我得到的错误如下。我相信这是在说这两个 ConcatenatingAudioSource
不一样,它们应该在哪里。
Expected: <Instance of 'ConcatenatingAudioSource'>
Actual: <Instance of 'ConcatenatingAudioSource'>
我从字面上复制了 audio_service
示例(第 362 行)中的转换部分,所以我真的很困惑这里出了什么问题。 (当我的实际应用程序是 运行 时,此转换代码也不起作用。我将测试的 actual
部分放在 setSource()
方法中,然后 play()
,但没有任何反应.)
如有任何帮助,我们将不胜感激!谢谢!
just_audio 不认为两个音频源相等,即使它们包含相同的元数据。这是因为每个副本都有自己的内部缓冲区和不同的内部状态。
您所能做的就是检查音频源中元数据的相等性。例如比较播放列表 a
和 b
:
ConcatenatingAudioSource a = ...;
ConcatenatingAudioSource b = ...;
expect(
a.children.map((s) => (s as UriAudioSource).uri).toList(),
b.children.map((s) => (s as UriAudioSource).uri).toList(),
);
我正在尝试 parse/convert MediaItem
列表到 ConcatenatingAudioSource
,但我的单元测试一直给我一个错误,即转换后的 ConcatenatingAudioSource
不匹配了解目标来源。我的测试是
List<MediaItem> audioSource = <MediaItem>[
MediaItem(
// This can be any unique id, but we use the audio URL for convenience.
id: "https://s3.amazonaws.com/scifri-episodes/scifri20181123-episode.mp3",
album: "Science Friday",
title: "A Salute To Head-Scratching Science",
artist: "Science Friday and WNYC Studios",
duration: Duration(milliseconds: 5739820),
artUri: Uri.parse(
"https://media.wnyc.org/i/1400/1400/l/80/1/ScienceFriday_WNYCStudios_1400.jpg"),
),
MediaItem(
id: "https://s3.amazonaws.com/scifri-segments/scifri201711241.mp3",
album: "Science Friday",
title: "From Cat Rheology To Operatic Incompetence",
artist: "Science Friday and WNYC Studios",
duration: Duration(milliseconds: 2856950),
artUri: Uri.parse(
"https://media.wnyc.org/i/1400/1400/l/80/1/ScienceFriday_WNYCStudios_1400.jpg"),
),
];
test('mediaItem2ConcatenatingAudioSource test', () {
expect(
// Here's where the conversion happens
ConcatenatingAudioSource(
children: audioSource
.map((item) => AudioSource.uri(Uri.parse(item.id)))
.toList(),
),
ConcatenatingAudioSource(children: [
AudioSource.uri(Uri.parse(
'https://s3.amazonaws.com/scifri-episodes/scifri20181123-episode.mp3')),
AudioSource.uri(Uri.parse(
"https://s3.amazonaws.com/scifri-segments/scifri201711241.mp3")),
]),
);
});
我得到的错误如下。我相信这是在说这两个 ConcatenatingAudioSource
不一样,它们应该在哪里。
Expected: <Instance of 'ConcatenatingAudioSource'>
Actual: <Instance of 'ConcatenatingAudioSource'>
我从字面上复制了 audio_service
示例(第 362 行)中的转换部分,所以我真的很困惑这里出了什么问题。 (当我的实际应用程序是 运行 时,此转换代码也不起作用。我将测试的 actual
部分放在 setSource()
方法中,然后 play()
,但没有任何反应.)
如有任何帮助,我们将不胜感激!谢谢!
just_audio 不认为两个音频源相等,即使它们包含相同的元数据。这是因为每个副本都有自己的内部缓冲区和不同的内部状态。
您所能做的就是检查音频源中元数据的相等性。例如比较播放列表 a
和 b
:
ConcatenatingAudioSource a = ...;
ConcatenatingAudioSource b = ...;
expect(
a.children.map((s) => (s as UriAudioSource).uri).toList(),
b.children.map((s) => (s as UriAudioSource).uri).toList(),
);