Laravel

Question

我正在使用 Laravel-5.8 和 Guzzle 来消耗外部 api:

public  function index()
{
    try{
    $myparam = 'JKK123';
    $client = new Client();
    $res = $client->request('GET','https://examplet/tracking/$myparam', [
       'query' => ['key' => 'jkkffd091']
   ])->getBody();
    $geoLocation = json_decode($res->getContents(), true);
    $currentLocation = collect($geoLocation)->sortByDesc(function ($data) {
        return Carbon::parse($data['Timestamp'])->format('d-m-Y h:i:s');
    })->first();  

    $currentLocationFilter = explode(',', $currentLocation['current_asset_position_coord'] ?? '');
    dd($currentLocationFilter);
    return view('index', [
        'currentLocation' => $currentLocation,
        'currentLocationFilter' => $currentLocationFilter,
        'geoLocation' => $geoLocation
    ]);
    }catch (Exception $exception) {
        Log::error($exception);
        return back();
    }
}

我正在尝试将变量作为参数传递给 API。我没有直接放，因为它会改变。我只是想测试一下。

当我按照上面的代码执行此操作时

$res = $client->request('GET','https://examplet/tracking/$myparam', [ ...

然后

dd($currentLocationFilter);

我得到了：

array:1 [▼
 0 => ""
]

但是当我直接放值的时候，

$res = $client->request('GET','https://examplet/tracking/JKK123', [

我得到了要求的结果：

 array:2 [▼
  0 => "2.1234565432145"
  1 => "1.7864321249555"
]

如何将变量作为参数传递到外部 API？

谢谢

Answer 1

像这样使用double quotes for executing variable：

$res = $client->request('GET',"https://examplet/tracking/{$myparam}", [...

Laravel - 如何使用 guzzle 将变量作为参数传递给外部 API

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