在 Lambda 函数中从 AWS Secrets Manager 检索机密

Retrieve secrets from AWS Secrets Manager in a Lambda function

我一直在尝试在 AWS 的 lambda 函数中使用 Secret Manager。

我正在使用 Secret Manager 存储我的 Redshift 凭据,并希望使用 AWS Secret Manager 提供的示例代码通过 lambda 函数检索密钥。

我在 Secret Manager 中设置了一个 Secret,其中包含我的 redshift 凭据(用户名、密码)

我正在尝试设置一个 lambda 函数,它将从 Secret Manger 获取秘密:下面是示例代码:


import boto3
import base64
from botocore.exceptions import ClientError


def lambda_handler(event, context):
    
    def get_secret():
        secret_name = "test/MySecret"
        region_name = "eu-west-2"

    # Create a Secrets Manager client
    session = boto3.session.Session()
    client = session.client(
        service_name='secretsmanager',
        region_name=region_name
    )
    
    try:
        get_secret_value_response = client.get_secret_value(
            SecretId = secret_name
        )
    except ClientError as e:
        if e.response['Error']['Code'] == 'DecryptionFailureException':
            # Secrets Manager can't decrypt the protected secret text using the provided KMS key.
            # Deal with the exception here, and/or rethrow at your discretion.
            raise e
        elif e.response['Error']['Code'] == 'InternalServiceErrorException':
            # An error occurred on the server side.
            # Deal with the exception here, and/or rethrow at your discretion.
            raise e
        elif e.response['Error']['Code'] == 'InvalidParameterException':
            # You provided an invalid value for a parameter.
            # Deal with the exception here, and/or rethrow at your discretion.
            raise e
        elif e.response['Error']['Code'] == 'InvalidRequestException':
            # You provided a parameter value that is not valid for the current state of the resource.
            # Deal with the exception here, and/or rethrow at your discretion.
            raise e
        elif e.response['Error']['Code'] == 'ResourceNotFoundException':
            # We can't find the resource that you asked for.
            # Deal with the exception here, and/or rethrow at your discretion.
            raise e
    else:
        # Decrypts secret using the associated KMS CMK.
        # Depending on whether the secret is a string or binary, one of these fields will be populated.
        if 'SecretString' in get_secret_value_response:
            secret = get_secret_value_response['SecretString']
        else:
            decoded_binary_secret = base64.b64decode(get_secret_value_response['SecretBinary'])

我在 运行 lambda 函数时遇到以下错误:

{
  "errorMessage": "name 'secret_name' is not defined",
  "errorType": "NameError",
  "stackTrace": [
    "  File \"/var/task/lambda_function.py\", line 22, in lambda_handler\n    SecretId = secret_name\n"
  ]
}

我在 lambda 函数的开头定义了 secret_name,但我收到 secret_name' is not defined 错误。关于如何解决问题的任何建议

所以问题是 python 无法获取 secret_name 变量的值,原因是它在一个函数下

def get_secret():
    secret_name = "test/MySecret"
    region_name = "eu-west-2"

所以如果你只是使用 secret_name = "test/MySecret" 没有函数部分,示例代码应该可以工作

在您的代码中添加 VersionStage 参数!

get_secret_value_response = client.get_secret_value(
            SecretId = secret_name,VersionStage='AWSCURRENT')