使用 ajax/datatables 获取数据并在没有 refreshing/reloading 页面的情况下对其进行排序
fetch data and sort it without refreshing/reloading the page using ajax/datatables
问题:我希望每次插入数据并从 sweetalert 弹出窗口中单击确定时,table 会自动获取新插入的数据并且应该已经在
升序。
我尝试过的解决方案:
我尝试过,每次插入成功时,它都会下降到 table 的末尾,这不是 suitable 并且需要重新加载才能排序,我使用 .append() 来获取新数据.
我正在为我的 table 使用 DataTables 插件。
我现在的设置是每次插入数据时我都必须重新加载页面,我认为这不太好,因为我正在使用 ajax。我正在使用 location.href = "URL"
有什么办法可以在不刷新页面的情况下刷新 table 页面吗?
addingUser.js
$(document).ready(function(){
$('#addStudent').click(function(e){
e.preventDefault();
Swal.fire({
title: "Are you sure?",
text: "New student will be added added!",
icon: "success",
showCancelButton: true,
allowEscapeKey : false,
allowOutsideClick: false
}).then((result) => {
if (result.isConfirmed) {
var valid = this.form.checkValidity();
if(valid){
// The studentNumberId should be the basis whether to know if the user is already existing
var studentNumberId = $('#studentNumberId').val();
var studentFullName = $('#studentFullName').val();
var studentPassword = $('#studentPassword').val();
var studentEmail = $('#studentEmail').val();
var studentYearBlock = $('#studentYearBlock').val();
e.preventDefault()
$.ajax({
type: 'POST',
url: 'includes/model_addStudent.php',
data: {studentNumberId: studentNumberId,studentFullName: studentFullName,studentPassword: studentPassword,studentEmail: studentEmail,
studentYearBlock: studentYearBlock},
success: function(data){
if(data === "true"){
// swal if the adding failed.
Swal.fire({
title: "Adding Failed",
text: "Student Already Existing",
icon: "warning"
}).then((result) => {
if (result.isConfirmed) {
$('#addModalStudent').modal('hide').find("input").val('');
}
});
}
else {
// it fetch without reloading but it adds at the bottom and needs to reload the sort the data. Solution that I tried //
/*
$('#tbl_manageStudents').append(`
<tr>
<td>${studentNumberId}</td>
<td>${studentFullName}</td>
<td>${studentEmail}</td>
<td>${studentYearBlock}</td>
</td>
<td>
<input type="submit" name="viewStudents" id="viewStudents" value="View" class="btn btn-info"
data-toggle="modal" data-target="#viewExistingStudents<?php echo $row["ID"];?>
<input type="submit" name="deleteRecord" id="deleteRecord" value="Delete" class="btn btn-danger"
data-toggle="modal" data-target="#deleteSelectedStudent<?php echo $row["ID"];?>
</td>
`);
*/
// swal if the user was successfully added
Swal.fire({
title: "Successfully Added!",
text: "New student has been added!",
icon: "success"
}).then((result) => {
if (result.isConfirmed) {
// current set up
location.href = "ManageStudents.php"
$('#addModalStudent').modal('hide').find("input").val('');
// $('#tbl_manageStudents').load("./helper/helper_tblManageStudent.php");
}
});
}
},
error: function(xhr, thrownError, ajaxOptions){
Swal.fire({
title: xhr,
text: thrownError,
icon: "info"
})
}
});
}
else {
Swal.fire({
title: "Error!",
text: "Invalid Form",
icon: "warning"
});
}
}
else {
Swal.fire(
'No Changes!',
'No New Student has been added.',
'info'
)
}
});
});
});
ManageUsers.php
<div class="container-sm table-responsive" id="tblManageStudent">
<table class="table table-striped table-hover table-condense" id="tbl_manageStudents">
<thead>
<tr>
<th scope="col">Student ID</th>
<th scope="col">Student Name</th>
<th scope="col">Student Email</th>
<th scope="col">Student Year and Block</th>
<th scope="col">Action</th>
</tr>
</thead>
<tbody>
<tr>
<!-- Change the tbl to tbl_students -->
<?php
include 'helper/helper_tblManageStudent.php';
?>
</tbody>
</table>
</div>
helper_tblManageStudents.php
<?php
include 'includes/connection_operation.php';
$sql = "SELECT * FROM tbl_students ORDER BY ( 0 + student_id ) ASC";
$query = mysqli_query($conn,$sql);
if($query)
{
while($row = mysqli_fetch_assoc($query))
{
?>
<td><?php echo $row['student_id']; ?></td>
<td><?php echo $row['student_name']; ?></td>
<td><?php echo $row['student_email']; ?></td>
<td><?php echo $row['student_yrblock']; ?></td>
<td>
<input type="submit" name="viewStudents" id="viewStudents" value="View" class="btn btn-info"
data-toggle="modal" data-target="#viewExistingStudents<?php echo $row["ID"];?>">
<input type="submit" name="deleteRecord" id="deleteRecord" value="Delete" class="btn btn-danger"
data-toggle="modal" data-target="#deleteSelectedStudent<?php echo $row["ID"];?>">
</td>
</tr>
<?php
include './helper/helper_viewExistingStudents.php';
include './helper/helper_deleteSelectedStudent.php';
}
}
?>
有没有办法在不刷新实际页面的情况下用新插入的数据重新加载helper_tblManageStudents.php的table并获取数据?
我使用数据表 API 通过 ajax 从服务器获取数据并在不重新加载页面的情况下刷新数据。我创建了一个 javascript 方法来处理数据加载并在创建记录后调用此方法。
- 在您的视图中像这样创建您的 table
<table id="dataTable" width="100%">
<thead>
<tr>
<th>Name</th>
<th>Email</th>
<th>Tel</th>
<th>Action</th>
</tr>
</thead>
<tbody>
</tbody>
</table>
- 导入 DataTable files 包括 jquery,创建 js 文件并粘贴此代码
<script type="text/javascript">
$(document).ready(function(){
function getData(){
$('#dataTable').DataTable( {
'processing':true,
'destroy':true,
'order': [],
'ajax': {
url: "path/users.php",//path to your server file
type: 'POST'
},
lengthChange: true,
lengthMenu: [
[ 10, 25, 50, -1 ],
[ '10 rows', '25 rows', '50 rows', 'Show all' ]
]
});
}
getData();
})
</script>
- users.php
<?php
// Create connection to db with server credentials
$conn = new mysqli($servername, $username, $password);
$sql = "SELECT name, email, tel FROM users ORDER BY id DESC";
$result = $conn->query($sql);
$output = array('data' => array());
if ($result->num_rows > 0) {
while($row = $result->fetch_assoc()) {
$name = htmlentities($row["name"]);
$email = htmlentities($row["email"]);
$tel = htmlentities($row["tel"]);
$status = htmlentities($row["status"]);
//EDITED
$action = "<button class='btn btn-primary'>View User</button> <button class='btn btn-primary'>Delete User</button>";
$output['data'][] = array(
$name,
$email,
$tel,
$action //EDITED
);
}
}
echo json_encode($output);
$conn->close();
?>
已编辑:我添加了适合您情况的按钮。您需要做的就是遍历按钮并连接它们。
问题:我希望每次插入数据并从 sweetalert 弹出窗口中单击确定时,table 会自动获取新插入的数据并且应该已经在 升序。
我尝试过的解决方案: 我尝试过,每次插入成功时,它都会下降到 table 的末尾,这不是 suitable 并且需要重新加载才能排序,我使用 .append() 来获取新数据.
我正在为我的 table 使用 DataTables 插件。
我现在的设置是每次插入数据时我都必须重新加载页面,我认为这不太好,因为我正在使用 ajax。我正在使用 location.href = "URL"
有什么办法可以在不刷新页面的情况下刷新 table 页面吗?
addingUser.js
$(document).ready(function(){
$('#addStudent').click(function(e){
e.preventDefault();
Swal.fire({
title: "Are you sure?",
text: "New student will be added added!",
icon: "success",
showCancelButton: true,
allowEscapeKey : false,
allowOutsideClick: false
}).then((result) => {
if (result.isConfirmed) {
var valid = this.form.checkValidity();
if(valid){
// The studentNumberId should be the basis whether to know if the user is already existing
var studentNumberId = $('#studentNumberId').val();
var studentFullName = $('#studentFullName').val();
var studentPassword = $('#studentPassword').val();
var studentEmail = $('#studentEmail').val();
var studentYearBlock = $('#studentYearBlock').val();
e.preventDefault()
$.ajax({
type: 'POST',
url: 'includes/model_addStudent.php',
data: {studentNumberId: studentNumberId,studentFullName: studentFullName,studentPassword: studentPassword,studentEmail: studentEmail,
studentYearBlock: studentYearBlock},
success: function(data){
if(data === "true"){
// swal if the adding failed.
Swal.fire({
title: "Adding Failed",
text: "Student Already Existing",
icon: "warning"
}).then((result) => {
if (result.isConfirmed) {
$('#addModalStudent').modal('hide').find("input").val('');
}
});
}
else {
// it fetch without reloading but it adds at the bottom and needs to reload the sort the data. Solution that I tried //
/*
$('#tbl_manageStudents').append(`
<tr>
<td>${studentNumberId}</td>
<td>${studentFullName}</td>
<td>${studentEmail}</td>
<td>${studentYearBlock}</td>
</td>
<td>
<input type="submit" name="viewStudents" id="viewStudents" value="View" class="btn btn-info"
data-toggle="modal" data-target="#viewExistingStudents<?php echo $row["ID"];?>
<input type="submit" name="deleteRecord" id="deleteRecord" value="Delete" class="btn btn-danger"
data-toggle="modal" data-target="#deleteSelectedStudent<?php echo $row["ID"];?>
</td>
`);
*/
// swal if the user was successfully added
Swal.fire({
title: "Successfully Added!",
text: "New student has been added!",
icon: "success"
}).then((result) => {
if (result.isConfirmed) {
// current set up
location.href = "ManageStudents.php"
$('#addModalStudent').modal('hide').find("input").val('');
// $('#tbl_manageStudents').load("./helper/helper_tblManageStudent.php");
}
});
}
},
error: function(xhr, thrownError, ajaxOptions){
Swal.fire({
title: xhr,
text: thrownError,
icon: "info"
})
}
});
}
else {
Swal.fire({
title: "Error!",
text: "Invalid Form",
icon: "warning"
});
}
}
else {
Swal.fire(
'No Changes!',
'No New Student has been added.',
'info'
)
}
});
});
});
ManageUsers.php
<div class="container-sm table-responsive" id="tblManageStudent">
<table class="table table-striped table-hover table-condense" id="tbl_manageStudents">
<thead>
<tr>
<th scope="col">Student ID</th>
<th scope="col">Student Name</th>
<th scope="col">Student Email</th>
<th scope="col">Student Year and Block</th>
<th scope="col">Action</th>
</tr>
</thead>
<tbody>
<tr>
<!-- Change the tbl to tbl_students -->
<?php
include 'helper/helper_tblManageStudent.php';
?>
</tbody>
</table>
</div>
helper_tblManageStudents.php
<?php
include 'includes/connection_operation.php';
$sql = "SELECT * FROM tbl_students ORDER BY ( 0 + student_id ) ASC";
$query = mysqli_query($conn,$sql);
if($query)
{
while($row = mysqli_fetch_assoc($query))
{
?>
<td><?php echo $row['student_id']; ?></td>
<td><?php echo $row['student_name']; ?></td>
<td><?php echo $row['student_email']; ?></td>
<td><?php echo $row['student_yrblock']; ?></td>
<td>
<input type="submit" name="viewStudents" id="viewStudents" value="View" class="btn btn-info"
data-toggle="modal" data-target="#viewExistingStudents<?php echo $row["ID"];?>">
<input type="submit" name="deleteRecord" id="deleteRecord" value="Delete" class="btn btn-danger"
data-toggle="modal" data-target="#deleteSelectedStudent<?php echo $row["ID"];?>">
</td>
</tr>
<?php
include './helper/helper_viewExistingStudents.php';
include './helper/helper_deleteSelectedStudent.php';
}
}
?>
有没有办法在不刷新实际页面的情况下用新插入的数据重新加载helper_tblManageStudents.php的table并获取数据?
我使用数据表 API 通过 ajax 从服务器获取数据并在不重新加载页面的情况下刷新数据。我创建了一个 javascript 方法来处理数据加载并在创建记录后调用此方法。
- 在您的视图中像这样创建您的 table
<table id="dataTable" width="100%">
<thead>
<tr>
<th>Name</th>
<th>Email</th>
<th>Tel</th>
<th>Action</th>
</tr>
</thead>
<tbody>
</tbody>
</table>
- 导入 DataTable files 包括 jquery,创建 js 文件并粘贴此代码
<script type="text/javascript">
$(document).ready(function(){
function getData(){
$('#dataTable').DataTable( {
'processing':true,
'destroy':true,
'order': [],
'ajax': {
url: "path/users.php",//path to your server file
type: 'POST'
},
lengthChange: true,
lengthMenu: [
[ 10, 25, 50, -1 ],
[ '10 rows', '25 rows', '50 rows', 'Show all' ]
]
});
}
getData();
})
</script>
- users.php
<?php
// Create connection to db with server credentials
$conn = new mysqli($servername, $username, $password);
$sql = "SELECT name, email, tel FROM users ORDER BY id DESC";
$result = $conn->query($sql);
$output = array('data' => array());
if ($result->num_rows > 0) {
while($row = $result->fetch_assoc()) {
$name = htmlentities($row["name"]);
$email = htmlentities($row["email"]);
$tel = htmlentities($row["tel"]);
$status = htmlentities($row["status"]);
//EDITED
$action = "<button class='btn btn-primary'>View User</button> <button class='btn btn-primary'>Delete User</button>";
$output['data'][] = array(
$name,
$email,
$tel,
$action //EDITED
);
}
}
echo json_encode($output);
$conn->close();
?>
已编辑:我添加了适合您情况的按钮。您需要做的就是遍历按钮并连接它们。