将JSON转换成oracle中JSON_VALUE可以读取的格式

Question

我有 JSON 格式的数据 -

{"dims":{"ABC":{"dim":"ABC","bins":{"1290":{"bin":"1290","hits":"1","first_date":"03.11.15"},"345":{"bin":"345","hits":"2","first_date":"03.11.15"},"6603":{"bin":"6603","hits":"1","first_date":"23.12.15"},"6609":{"bin":"6609","hits":"1","first_date":"13.12.15"}}}}}

如何将其转换成格式-

{"dims":{"BINDUNGS_ID_CARDS":{"dim":"BINDUNGS_ID_CARDS","bins":[{"bin":"1290","hits":"1","first_date":"03.11.15"},{"bin":"345","hits":"2","first_date":"03.11.15"},{"bin":"6603","hits":"1","first_date":"23.12.15"},{"bin":"6609","hits":"1","first_date":"13.12.15"}]}}}

我想通过 JSON_VALUE(value, $.*.*.bins[0]) 使用 JSON_VALUE 函数从 oracle 读取它。

我不知道如何通过 oracle 实现它。

Answer 1

您可以使用以下方法重新格式化它：

SELECT j.*
FROM   table_name t
       CROSS APPLY (
         SELECT JSON_OBJECT(
                   'dims' VALUE JSON_OBJECT(
                     'BINDUNGS_ID_CARDS' VALUE JSON_OBJECT(
                       'dims' VALUE 'BINDUNGS_ID_CARDS',
                       'bins' VALUE JSON_ARRAYAGG(
                         data FORMAT JSON ORDER BY ROWNUM
                       )
                     )
                   )
                ) As value
         FROM   JSON_TABLE(
                  t.value,
                  '$.*.*.bins.*'
                  COLUMNS (
                    data CLOB FORMAT JSON PATH '$'
                  )
                )
       ) j

其中，对于示例数据：

CREATE TABLE table_name ( value CLOB CHECK ( value IS JSON ) );

INSERT INTO table_name ( value )
VALUES (
'{
  "dims":{
    "ABC":{
      "dim":"ABC",
      "bins":{
        "1290":{"bin":"1290","hits":"1","first_date":"03.11.15"},
        "345":{"bin":"345","hits":"2","first_date":"03.11.15"},
        "6603":{"bin":"6603","hits":"1","first_date":"23.12.15"},
        "6609":{"bin":"6609","hits":"1","first_date":"13.12.15"}
      }
    }
  }
}' );

输出：

| VALUE                                                                                                                                                                                                                                                                       |
| :-------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------- |
| {"dims":{"BINDUNGS_ID_CARDS":{"dims":"BINDUNGS_ID_CARDS","bins":[{"bin":"1290","hits":"1","first_date":"03.11.15"},{"bin":"345","hits":"2","first_date":"03.11.15"},{"bin":"6603","hits":"1","first_date":"23.12.15"},{"bin":"6609","hits":"1","first_date":"13.12.15"}]}}} |

然而，这感觉像是一个 XY 问题。

I want to read it from oracle using JSON_VALUE function via JSON_VALUE(value, $.*.*.bins[0]).

如果你想要对象的第一个值那么你不需要重新格式化 JSON 并且可以直接使用：

SELECT bin,
       hits,
       TO_DATE( first_date, 'DD.MM.RR' ) AS first_date
FROM   table_name t
       CROSS APPLY JSON_TABLE(
         t.value,
         '$.*.*.bins.*'
         COLUMNS (
           rn         FOR ORDINALITY,
           bin        VARCHAR2(20) PATH '$.bin',
           hits       VARCHAR2(20) PATH '$.hits',
           first_date VARCHAR2(8) PATH '$.first_date'
         )
       ) j
WHERE  rn = 1

输出：

BIN  | HITS | FIRST_DATE         
:--- | :--- | :------------------
1290 | 1    | 2015-11-03 00:00:00

db<>fiddle here

将JSON转换成oracle中JSON_VALUE可以读取的格式

Convert JSON in a format can be read by JSON_VALUE in oracle

json

oracle

oracle12c