如何仅从 6 小时数据集立方体（虹膜）中绘制每小时的数据？

Question

到目前为止，我绘制图表的代码如下所示：

iplt.plot(pressure_no1, color='black')
plt.xlabel('Time / hour of day')
plt.ylabel('Atmospheric pressure / kPa')
iplt.show()

这是一个6小时的立方体（虽然是二维的）数据集，有420个数据点。我只需要绘制数据点 hr=0, hr=1 hr=2, hr=3, hr=4, hr=5 和小时之间的 none。

像下面这样的东西可以工作吗？

pressure_no1_hrs = pressure_no1.coord('hour'==int).points
plt.plot(pressure_no1_hrs)

Image of graph with all data points and start of the time coordinates Image of last lot of time coordinates

Answer 1

import matplotlib.pyplot as plt
import numpy as np
import pandas as pd


measures = np.random.normal(size=(360, ))
timepoints = np.arange(start=0, stop=360)


df = pd.DataFrame({'measure': measures, 'timepoint': timepoints})

is_hour = df.loc[:, 'timepoint'] % 60 == 0  # <- Only select full hour

plt.plot(df.loc[is_hour, 'measure'])
plt.xlabel("Time [min]")
plt.ylabel("Atmospheric pressure / kPa")
plt.show()

Answer 2

对于特定于 Iris 的解决方案，您可以使用 PartialDateTime:

import iris
import iris.quickplot as qplt
import numpy as np
import matplotlib.pyplot as plt

measures = np.random.normal(size=(360, ))
timepoints = np.arange(start=0, stop=360)

cube = iris.cube.Cube(measures, long_name='atmospheric_pressure', units='kPa')
time_coord = iris.coords.DimCoord(
    timepoints, units='minutes since 2020-07-01 00:00', standard_name='time')
cube.add_dim_coord(time_coord, 0)

subcube = cube.extract(iris.Constraint(time=iris.time.PartialDateTime(minute=0)))

qplt.plot(cube, label='All data')
qplt.plot(subcube, label='Hourly data')

plt.legend()

plt.show()

如何仅从 6 小时数据集立方体（虹膜）中绘制每小时的数据？

How to only plot data on the hour from a 6 hour dataset cube (iris)?

python

matplotlib

python-iris

iris-dataset