在我的数组中找到中位数，同时将数字从最小到最大排序

Question

这是我目前所做的；我能够计算平均值，但我不确定如何找到中位数。我也知道我需要对数组进行排序以使其更容易。

 public class SAA {
     public static void main(String[] args) {
         int[] num = {60, 70, 82, 1216, 57, 82, 34, 560, 91, 86};
         int total = 0;
         for (int i = 0; i < num.length; i++) {
             if ((num[i] > 0) && (num[i] < 100)) {
                 total += num[i];
             }
         }
         System.out.println(total / 10);
     }
 }

这是我使用冒泡排序的尝试：

public class Bubblesort {
    public static void main(String[] args) {
        int[] num = {60, 70, 82, 1216, 57, 82, 34, 560, 91, 86};
        int temp = 0;
        int[] add = new int[num.length + 1];
        for (int i = 0; i < num.length; i++) {
            for (int j = i + 1; j < num.length; j++) {
                if (num[i] > num[j]) {
                    temp = num[i];
                    num[i] = num[j];
                    num[j] = temp;
                }
            }
        }
        for (int i = 0; i < num.length; i++) {
            System.out.print(num[i] + " ");
        }
    }
}

Answer 1

如果数组大小为奇数，则中位数为排序数组的中间元素，否则为中间两个元素的平均值。以下代码片段查找数组的中位数。

public static void main(String[] args) {
        int[]num = {60, 70, 82, 1216, 57, 82, 34, 560, 91, 86};
        int median;
        int len = num.length;
        
        Arrays.sort(num); // sorts the array
        
        //check if the length is odd
        if(len%2 != 0)
            median = num[len/2];
        else // length is even
            median = (num[(len - 1) / 2] + num[len / 2])/2;
        System.out.println(median);
    }

Answer 2

        int min = 0; 
        int max = 0; 
        
        for (int i = 0; i < numbers.length; i++)
        {
            for (int j = 0; j < numbers.length-1; j++)
            {
                min = Math.min(numbers[j], numbers[j+1]); //using min and max methods
                max = Math.max(numbers[j], numbers[j+1]); 
                numbers[j] = min; //placing the smaller value on the left
                numbers[j+1] = max; //placing the larger value on the right
            }
        }

这是一个以简短的方式对数组进行冒泡排序的程序，您也应该将它与@Sr_33的答案一起使用！

在我的数组中找到中位数，同时将数字从最小到最大排序

Find the median in my array while also sorting the numbers from smallest to largest

java

bubble-sort

median