从 STEP 文件中提取体积

Question

我的目标是编写一个 Python 程序来提取 STEP 文件中对象的体积。我能够找到 steputils and aoxchange are the two libraries present in Python but neither of them seemed to contain enough documentation about extracting the volume/properties from the file. Is there any document available that can explain this? I tried a similar use-case for STL files and was able to achieve it successfully using numpy-stl。我正在为 STEP 文件搜索类似 numpy-stl 的东西。下面是我如何为 STL 个文件实现它的示例代码。

import numpy
from stl import mesh
your_mesh = mesh.Mesh.from_file('/path/to/myfile.stl')
volume, cog, inertia = your_mesh.get_mass_properties()
print("Volume = {0}".format(volume))

Answer 1

编辑以考虑 gkv311 的建议：pythonOCC 可用于直接计算体积。

from OCC.Core.GProp import GProp_GProps
from OCC.Core.BRepGProp import brepgprop_VolumeProperties
from OCC.Extend.DataExchange import read_step_file

my_shape = read_step_file(path_to_file)
prop = GProp_GProps()
tolerance = 1e-5 # Adjust to your liking
volume = brepgprop_VolumeProperties(myshape, prop, tolerance)
print(volume)

旧版本，使用STEP到STL转换。

绝对不是最优雅的解决方案，但它完成了工作：使用Pythonocc（库aoxchange基于），你可以转换一个STEP 文件到 STL，然后使用问题的解决方案计算 STL 的体积。

from OCC.Core.STEPControl import STEPControl_Reader
from OCC.Core.StlAPI import StlAPI_Writer

input_file  = 'myshape.stp'
output_file = 'myshape.stl'

# Load STEP file
step_reader = STEPControl_Reader()
step_reader.ReadFile( input_file )
step_reader.TransferRoot()
myshape = step_reader.Shape()
print("File loaded")

# Export to STL
stl_writer = StlAPI_Writer()
stl_writer.SetASCIIMode(True)
stl_writer.Write(myshape, output_file)
print("Done")

从 STEP 文件中提取体积

Extract volume from a STEP file

python

step

python-3.x